如何从控制台应用程序JAVA中的扫描仪读取字符串？

问题描述

import java.util.Scanner;
class MyClass
{
     public static void main(String args[]){

                Scanner scanner = new Scanner(System.in);
                int eid,sid;
                String ename;
                System.out.println("Enter Employeeid:");
                     eid=(scanner.nextInt());
                System.out.println("Enter EmployeeName:");
                     ename=(scanner.next());
                System.out.println("Enter SupervisiorId:");
                      sid=(scanner.nextInt());  
        }
}

我在输入时尝试输入

Enter Employeeid:
101
Enter EmployeeName:
firstname lastname
Enter SupervisiorId:
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at com.controller.Menu.<init>(Menu.java:61)
    at com.tests.Employeetest.main(Employeetest.java:17)

但是在此工作

Enter Employeeid:
105
Enter EmployeeName:
name
Enter SupervisiorId:
501

我想要的是我必须阅读完整的字符串是否它以 name 或 firstname lastname 给出。例如： - （ john - >是由scanner.next（）接受;但是scan.next（）不接受 john carter ; ）

What I want is that i must read the full string whether it is given as name or as firstname lastname..Eg:-(john --> is accepted by scanner.next(); but john carter is not accepted by scanner.next(); )

推荐答案

import java.util.Scanner;

class MyClass
{
     public static void main(String args[]){

                Scanner scanner = new Scanner(System.in);
                int eid,sid;
                String ename;
                System.out.println("Enter Employeeid:");
                eid=scanner.nextInt();
                scanner.nextLine(); //This is needed to pick up the new line
                System.out.println("Enter EmployeeName:");
                ename=scanner.nextLine();
                System.out.println("Enter SupervisiorId:");
                sid=(scanner.nextInt());  
        }
}

调用nextInt（）是一个问题，因为它没有'拿起新线（当你按下回车键）。因此，在此之后调用scanner.nextLine（）可以正常工作。

Calling nextInt() was a problem as it didn't pick up the new line (when you hit enter). So, calling scanner.nextLine() after that does the work.

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