当我尝试运行我的代码时，它显示编译器停止工作，任何人都可以告诉我原因

问题描述

#include<stdio.h>
#include<stdio.h>
int main()
{
    char *s[] = {
                    "To err is human...",
                    "But to really mess things up",
                    "One needs to know C!!"
                }, rev[3][30];
    int a;
    for(a = 0; a <3; a++)
    {
        rev[a][0] = strrev(*s[a]);
        printf("%s", rev[a][0]);
    }
    return 0;
}

我的尝试：



试图通过一些修改编译几次但没有发生任何事情

What I have tried:

Tried to compile it several times with a few modifications but nothing is happening

推荐答案

int main()
{
    char *s[] = { "To err is human...",
                    "But to really mess things up",
                    "One needs to know C!!"
                };
    int a;
    for(a = 0; a <3; a++)
    {
        printf(/*"%s",*/ strrev(s[a]);
    }
    return 0;
}

引用：

char * s [] = {

犯错误就是人......，

但真的搞砸了，

人们需要知道C !!

}

char *s[] = {
"To err is human...",
"But to really mess things up",
"One needs to know C!!"
}

您正在尝试修改只读内存。

尝试：

You are trying to modify read-only memory.
Try:

int main()
{
    char s[][30] = {
                    "To err is human...",
                    "But to really mess things up",
                    "One needs to know C!!"
                };
    int a;
    for(a = 0; a <3; a++)
    {
        printf("%s\n", strrev(s[a]));
    }
    return 0;
}

BTW strrev 是一个非标准功能，事实上我的系统无法使用。我用

草绘了它

BTW strrev is a not standard function, as a matter of fact unavailable on my system. I sketched it with

char * strrev(char * s)
{
  size_t len = strlen(s);
  size_t n;
  for (n=0; n<len/2; ++n)
  {
    char tmp = s[n];
    s[n] = s[len-1-n];
    s[len-1-n] = tmp;
  }  
  return s;
}

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