本文介绍了在Ruby中从哈希数组中删除哈希的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
[{k1=>v1，k2 =75.1％}，{k1=>v2，k2=> - NA-}，{k1=>v3，k2=> ;5.1％}]
现在，我想先检查数组是否包含散列键k1，其值v3。如果是，那么我想从数组中删除该散列。
结果应该是：
[{k1= >v1，k2=>75.1％}，{k1=>v2，k2=> - NA-}]
解决方案
使用：
arr = [{k1=>v1，k2=>75.1％}，{k1=>v2，k2= > - NA-}，{k1=>v3，k2=>5.1％}]
arr.delete_if {| h | h [k1] ==v3}
＃=> [{k1=>v1，k2=>75.1％}，{k1=>v2，k2=> - NA-}] $ b 如果没有匹配条件的哈希，数组保持不变。
I have an array of hashes as following:
[{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}]
Now, I want to first check whether the array contains a hash with key "k1" with value "v3". If yes, then I want to delete that hash from the array.
The result should be:
[{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]
解决方案
Use Array#delete_if:
arr = [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}]
arr.delete_if { |h| h["k1"] == "v3" }
#=> [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]
If there is no hash matching the condition, the array is left unchanged.
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