问题描述
我有一些带有特定于应用程序标签的 yaml(确切地说是来自 AWS Cloud Formation 模板),如下所示:
example_yaml = "名称: !Join [' ', ['EMR', !Ref 'Environment', !Ref 'Purpose']]"
我想解析它以便我可以这样做:
>>>打印(结果)>>>{'Name': 'EMR {环境} {目的}'}>>>name = result['name'].format(... 环境='发展',...目的='ETL'……)>>>打印(名称)>>>EMR 开发 ETL目前我的代码是这样的:
导入yaml从 pprint 导入 pprintdef aws_join(加载器,节点):join_args = loader.construct_yaml_seq(节点)分隔符 = 列表(join_args)[0]joinables = 列表(join_args)[1]join_result = delimiter.join(joinables)返回 join_resultdef aws_ref(loader, node):值 = loader.construct_scalar(节点)占位符 = '{'+值+'}'返回占位符yaml.add_constructor('!Join', aws_join)yaml.add_constructor('!Ref', aws_ref)example_yaml = "名称: !Join [' ', ['EMR', !Ref 'Environment', !Ref 'Purpose']]"pprint(yaml.load(example_yaml))
不幸的是,这会导致错误.
...joinables = 列表(join_args)[1]IndexError:列表索引超出范围
将 print('What I am: '+str(join_args))
添加到 aws_join
表明我得到了一个生成器:
我是什么:
这就是我尝试将生成器转换为列表的原因.不过,生成器最终会正确填充,只是我没有及时使用它.如果我将 aws_join
函数更改为这样:
def aws_join(loader, node):join_args = loader.construct_yaml_seq(节点)返回 join_args
那么最终的结果是这样的:
{'Name': [' ', ['EMR', '{Environment}', '{Purpose}']]}
所以我的函数所需的部分就在那里,只是当我在我的函数中需要它们时.
你已经接近了,但问题是你使用的方法construct_yaml_seq()
.该方法实际上是一个注册正常 YAML 序列的构造函数(最终使一个 Python 列表)并调用 construct_sequence()
方法来处理传入的节点,这也是您应该做的.
当您返回一个字符串时,该字符串无法处理递归数据结构,您不需要使用两步创建过程(首先yield
-ing,然后填写)其中的construct_yaml_seq()
方法如下.但是这两个步骤的创建过程是为什么你遇到了生成器.
construct_sequence
返回一个简单的列表,但是根据您的需要,节点在开始处理时可用的 !Join
下方,请确保指定deep=True
参数,否则第二个列表element 将是一个空列表.因为construct_yaml_seq()
,没有指定deep=True
,你没有及时得到碎片您的函数(否则您实际上可能会使用该方法).
导入yaml从 pprint 导入 pprintdef aws_join(加载器,节点):join_args = loader.construct_sequence(节点,深=真)# 你可以注释掉下一行断言 join_args == [' ', ['EMR', '{Environment}', '{Purpose}']]分隔符 = join_args[0]joinables = join_args[1]返回 delimiter.join(joinables)def aws_ref(loader, node):值 = loader.construct_scalar(节点)占位符 = '{'+值+'}'返回占位符yaml.add_constructor('!Join', aws_join, Loader=yaml.SafeLoader)yaml.add_constructor('!Ref', aws_ref, Loader=yaml.SafeLoader)example_yaml = "名称: !Join [' ', ['EMR', !Ref 'Environment', !Ref 'Purpose']]"pprint(yaml.safe_load(example_yaml))
给出:
{'Name': 'EMR {Environment} {Purpose}'}
你不应该使用 load()
,它被记录为潜在的不安全,最重要的是:这里没有必要.注册SafeLoader
并调用 safe_load()
I have some yaml with application-specific tags (from an AWS Cloud Formation template, to be exact) that looks like this:
example_yaml = "Name: !Join [' ', ['EMR', !Ref 'Environment', !Ref 'Purpose']]"
I want to parse it so that I can do this:
>>> print(result)
>>> {'Name': 'EMR {Environment} {Purpose}'}
>>> name = result['name'].format(
... Environment='Development',
... Purpose='ETL'
... )
>>> print(name)
>>> EMR Development ETL
Currently my code looks like this:
import yaml
from pprint import pprint
def aws_join(loader, node):
join_args = loader.construct_yaml_seq(node)
delimiter = list(join_args)[0]
joinables = list(join_args)[1]
join_result = delimiter.join(joinables)
return join_result
def aws_ref(loader, node):
value = loader.construct_scalar(node)
placeholder = '{'+value+'}'
return placeholder
yaml.add_constructor('!Join', aws_join)
yaml.add_constructor('!Ref', aws_ref)
example_yaml = "Name: !Join [' ', ['EMR', !Ref 'Environment', !Ref 'Purpose']]"
pprint(yaml.load(example_yaml))
Unfortunately this results in an error.
...
joinables = list(join_args)[1]
IndexError: list index out of range
Adding print('What I am: '+str(join_args))
to aws_join
shows that I'm getting a generator:
What I am: <generator object SafeConstructor.construct_yaml_seq at 0x1082ece08>
That's why I tried to cast the generator as a list. The generator eventually populates correctly though, just not in time for me to use it. If I change my aws_join
function to like this:
def aws_join(loader, node):
join_args = loader.construct_yaml_seq(node)
return join_args
Then the final result looks like this:
{'Name': [' ', ['EMR', '{Environment}', '{Purpose}']]}
So the required pieces to my function are there, just not when I need them in my function.
You are close, but the problem is that you are using the methodconstruct_yaml_seq()
. That method is actually a registeredconstructor for the normal YAML sequence (the one that eventually makesa Python list) and it calls the construct_sequence()
method to handle thenode that gets passed in, and that is what you should do as well.
As you are returning a string, which cannot deal with recursive datastructures, you don't need to use the two step creation process (firstyield
-ing, then filling out) which the construct_yaml_seq()
methodfollows. But this two step creation process is why you encountered agenerator.
construct_sequence
returns a simple list, but as you want the nodesunderneath the !Join
available when you start processing, make sureto specify the deep=True
parameter, otherwise the second listelement will be an empty list. And because construct_yaml_seq()
,doesn't specify deep=True
, you did not get the pieces in time inyour function (otherwise you could have actually used that method).
import yaml
from pprint import pprint
def aws_join(loader, node):
join_args = loader.construct_sequence(node, deep=True)
# you can comment out next line
assert join_args == [' ', ['EMR', '{Environment}', '{Purpose}']]
delimiter = join_args[0]
joinables = join_args[1]
return delimiter.join(joinables)
def aws_ref(loader, node):
value = loader.construct_scalar(node)
placeholder = '{'+value+'}'
return placeholder
yaml.add_constructor('!Join', aws_join, Loader=yaml.SafeLoader)
yaml.add_constructor('!Ref', aws_ref, Loader=yaml.SafeLoader)
example_yaml = "Name: !Join [' ', ['EMR', !Ref 'Environment', !Ref 'Purpose']]"
pprint(yaml.safe_load(example_yaml))
which gives:
{'Name': 'EMR {Environment} {Purpose}'}
You should not use load()
, it is documented to be potentiallyunsafe, and above all: it is not necessary here. Register with theSafeLoader
and call safe_load()
这篇关于解析嵌套的自定义 yaml 标签的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!