本文介绍了在Numpy/Scipy中切片数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个像这样的数组:
I have an array like:
a = array([[1,2,3],[3,4,5],[4,5,6]])
从其中仅包含"a"的前两列的1x2数组中切出的最有效方法是什么?
What's the most efficient way to slice out a 1x2 array out of this that has only the first two columns of "a"?
即
array([[2,3],[4,5],[5,6]]) in this case.
推荐答案
使用a[i,j]
(不是a[i][j]
)为二维numpy数组建立索引,但是您可以对numpy数组和矩阵使用相同的切片符号在python中使用普通矩阵(只需将它们放在单个[]
中):
Two dimensional numpy arrays are indexed using a[i,j]
(not a[i][j]
), but you can use the same slicing notation with numpy arrays and matrices as you can with ordinary matrices in python (just put them in a single []
):
>>> from numpy import array
>>> a = array([[1,2,3],[3,4,5],[4,5,6]])
>>> a[:,1:]
array([[2, 3],
[4, 5],
[5, 6]])
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