更有效的方法来提取地址组件

问题描述

Currenty, I'm using the following code to get the country, postal code, locality and sub-locality:

当前，我使用以下代码来获取国家，邮政编码，地区和子地点： var country，postal_code，locality，sublocality;对于（j = 0; j< results [0] .address_components，对于（i = 0; i< results [0] .address_components.length; ++ i）
{
） [i] .types.length; ++ j）
{
if（！country&& results [0] .address_components [i] .types [j] ==country）
country = results [0] .address_components [i] .long_name;
else if（！postal_code&& results [0] .address_components [i] .types [j] ==postal_code）
postal_code = results [0] .address_components [i] .long_name ;
else if（！locality&& results [0] .address_components [i] .types [j] ==locality）
locality = results [0] .address_components [i] .long_name ;
else if（！sublocality&& results [0] .address_components [i] .types [j] ==sublocality）
sublocality = results [0] .address_components [i] .long_name ;
}
}

var country, postal_code, locality, sublocality;for (i = 0; i < results[0].address_components.length; ++i){ for (j = 0; j < results[0].address_components[i].types.length; ++j) { if (!country && results[0].address_components[i].types[j] == "country") country = results[0].address_components[i].long_name; else if (!postal_code && results[0].address_components[i].types[j] == "postal_code") postal_code = results[0].address_components[i].long_name; else if (!locality && results[0].address_components[i].types[j] == "locality") locality = results[0].address_components[i].long_name; else if (!sublocality && results[0].address_components[i].types[j] == "sublocality") sublocality = results[0].address_components[i].long_name; }}

这并不令人满意。有没有其他方法可以达到同样的结果？

That's unsatisfactory. Is there any other way to achieve the same result?

推荐答案

if (typeof Object.keys == 'function')
    var length = function(x) { return Object.keys(x).length; };
else
    var length = function() {};

var location = {};
for (i = 0; i < results[0].address_components.length; ++i)
{
    var component = results[0].address_components[i];
    if (!location.country && component.types.indexOf("country") > -1)
        location.country = component.long_name;
    else if (!location.postal_code && component.types.indexOf("postal_code") > -1)
        location.postal_code = component.long_name;
    else if (location.locality && component.types.indexOf("locality") > -1)
        location.locality = component.long_name;
    else if (location.sublocality && component.types.indexOf("sublocality") > -1)
        location.sublocality = component.long_name;

    // nothing will happen here if `Object.keys` isn't supported!
    if (length(location) == 4)
        break;
}

这对我来说是最合适的解决方案。它也可以帮助别人。

This is the most suitable solution for me. It may help someone too.

这篇关于更有效的方法来提取地址组件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！