删除千位分隔符

问题描述

我导入了一个 Excel 文件并得到了这样的数据框

I imported an Excel file and got a data frame like this

structure(list(A = structure(1:3, .Label = c("1.100", "2.300",
"5.400"), class = "factor"), B = structure(c(3L, 2L, 1L), .Label = c("1.000.000",
"500", "7.800"), class = "factor"), C = structure(1:3, .Label = c("200",
"3.100", "4.500"), class = "factor")), .Names = c("A", "B", "C"
), row.names = c(NA, -3L), class = "data.frame")

我现在想将这些 chars 转换为 numeric 甚至 integer.但是，点字符 (.) 不是十进制符号，而是千位分隔符"(德语).

I would now like to convert these chars to numeric or even integer. However, the dot character (.) is not a decimal sign but a "thousand's separator" (it's German).

如何正确转换数据框?

我试过了:

df2 <- as.data.frame(apply(df1, 2, gsub, pattern = "([0-9])\\.([0-9])", replacement= "\\1\\2"))

df3 <- as.data.frame(data.matrix(df2))

然而，apply 似乎将每一列转换为一个因子列表.我可以阻止 apply 这样做吗?

however, apply seems to convert each column to a list of factors. Can I maybe prevent apply from doing so?

推荐答案

我想我刚刚找到了另一个解决方案:

I think I just found another solution:

必须使用stringsAsFactors = FALSE.

像这样:

df2 <- as.data.frame(apply(df1, 2, gsub, pattern = "([0-9])\\.([0-9])", replacement= "\\1\\2"), stringsAsFactors = FALSE)

df3 <- as.data.frame(data.matrix(df2))

这篇关于删除千位分隔符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！