本文介绍了刷新后如何保持ajax加载！的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
大家好！再次在这里有一个小问题！
我会直截了当！！
Hello everyone!! here again with a little problem!!
I will straightly go the point!!
<html>
<head>
<script type="text/javascript">
function loadXMLDoc()
{
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("test").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","info.php",true);
xmlhttp.send();
}
</script>
</head>
<body>
<div id="test"><h2>This is where the new text will be displayed</h2></div>
<button type="button" önClick="loadXMLDoc()">Change Content</button>
</body>
</html>
这是我在同一目录中的info.php文件！
And here is my info.php file in the same directory!!
echo "tarek";
?>
现在的问题是，当我单击按钮div会将我的结果更改为该PHP文件时，一切工作正常.但是，当我刷新页面时，它会返回到原始阶段！
刷新后，我想将其保存到info.php文件中.
Now the thing is that Everything is working fine when I click on the button the div is changing my result to that PHP file. But when I refresh the page it goes back in the original phase!!
I want to keep it to the info.php file after refresh!!!
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