问题描述
我试图写一个C程序进行总结和。减去两个复数。
这里的code:
I am trying to write a C program to sum and substract two complex numbers.Here's the code:
#include <stdlib.h>
#include <stdio.h>
typedef struct cplx
{
int re;
int im;
} cplx;
cplx* sum(cplx *x, cplx *y,int n)
{
cplx *z; int i;
for(i=0;i<n;i++)
{
z[i].re=x[i].re+y[i].re;
z[i].im=x[i].im+y[i].im;
}
return z;
}
cplx* difference(cplx *x, cplx *y, int n)
{
cplx *z; int i;
for(i=0;i<n;i++)
{
z[i].re=x[i].re-y[i].re;
z[i].im=x[i].im-y[i].im;
}
return z;
}
cplx* sumdiff(cplx *x,cplx *y, int n,cplx* (*op)())
{
return(op(x,y,n));
}
int main(void)
{
cplx *z1,*z2,*s,*diff;
int m,n,i;
printf("Give the number of complex numbers to add and substract:");
scanf("%d",&n);
z1=(cplx*)malloc(n*sizeof(cplx));
z2=(cplx*)malloc(n*sizeof(cplx));
s=(cplx*)malloc(n*sizeof(cplx));
diff=(cplx*)malloc(n*sizeof(cplx));
if ( z1==NULL || z2==NULL || s==NULL || diff==NULL)
{
printf("Allocation failed.\nEnding program.");
exit(0);
}
printf("Give the numbers of the first vector:\n");
for(i=0;i<n;i++)
{
printf("Re(z1[%d])=",i+1); scanf("%d",&m);
z1[i].re=m;
printf("Im(z1[%d])=",i+1); scanf("%d",&(z1[i].im));
}
printf("Give the numbers of the second vector:\n");
for(i=0;i<n;i++)
{
printf("Re(z2[%d])=",i+1); scanf("%d",&(z2[i].re));
printf("Im(z2[%d])=",i+1); scanf("%d",&(z2[i].im));
}
s=sum(z1,z2,n);
diff=difference(z1,z2,n);
s=sumdiff(z1,z2,n,sum);
diff=sumdiff(z1,z2,n,difference);
for(i=0;i<n;i++)
{
printf("z1[%d]+z2[%d]=%d+j(%d)\nz1[%d]+z2[%d]=%d+j(%d)\n",i+1,i+1,s[i+1].re,s[i+1].im,i,i,diff[i+1].re,diff[i+1].im);
}
free(z1); free(z2); free(s); free(diff);
return 0;
}
它编译罚款与海湾合作委员会,但是当我运行它,在执行前S = SUM(Z1,Z2,N)停止;段故障(核心转储)。
我在做什么错了?
It compiles fine with GCC but when I run it, the execution stops before s=sum(z1,z2,n); with a segmentation fault (core dumped).What am I doing wrong ?
推荐答案
以Z
在之
和区别
是一个未初始化的指针。你得到了一个未定义的行为(可能崩溃)当您尝试写这个。你需要在每一项功能以Z
分配内存。
z
in sum
and difference
is an uninitialised pointer. You get undefined behaviour (and likely a crash) when you try to write to this. You need to allocate memory for z
in each of these functions.
cplx* sum(cplx *x, cplx *y,int n)
{
cplx *z = malloc(n * sizeof(*z));
int i;
if (z == NULL) {
return NULL;
}
您还必须确保你免费
内存从这些函数返回。在code
You'll also have to make sure you free
the memory returned from these functions. The code
s=sum(z1,z2,n);
diff=difference(z1,z2,n);
s=sumdiff(z1,z2,n,sum);
diff=sumdiff(z1,z2,n,difference);
目前就这两个泄漏 S的第一个实例
和差异
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