本文介绍了如何根据语音命令打开Activity的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在做有很多屏幕的仪表板应用程序.当用户根据我需要打开活动时告诉语音命令.我不知道从哪里开始我已经完成了所有屏幕,我想实现语音搜索.我的应用程序屏幕是预付款、休假、招聘、权限、通知等示例:当用户说Advances"时,它应该打开Advances"屏幕.请帮帮我.

I am doing dashboard application in which there are lot of screens. When the user tell the voice command based on that I need to open the activity. I don't know where to start I have already completed all the screens and I would like to implement voice search.my app screens are Advances, Leaves, Recruitment, Permissions, Notifications etcExample: when the user say 'Advances' it should open the advances screens. Please help me.

推荐答案

1) 启动语音识别 Intent

1) Start a voice recognition intent

2) 处理onActivityResult()中返回的数据来决定启动哪个Activity

2) Handle the returned data in onActivityResult() to decide which activity to start

1.启动语音识别意图

Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_PROMPT, "Choose Activity");
startActivityForResult(intent, REQUEST_SPEECH);

2.处理返回的数据

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data){
        if (requestCode == REQUEST_SPEECH){
            if (resultCode == RESULT_OK){
                ArrayList<String> matches = data
                    .getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);

                if (matches.size() == 0) {
                    // didn't hear anything
                } else {
                    String mostLikelyThingHeard = matches.get(0);
                    // toUpperCase() used to make string comparison equal
                    if(mostLikelyThingHeard.toUpperCase().equals("ADVANCES")){
                        startActivity(new Intent(this, Advances.class));
                    } else if() {
                    }
                }
            }
        }

        super.onActivityResult(requestCode, resultCode, data);
    }

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07-23 15:07
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