问题描述
我正在尝试从我的 UIViewController 切换回我的 UITableViewController 但显然它没有按照我想要的方式工作.我确实从一开始就用故事板创建了我的界面,所以我并没有真正通过代码从一个视图移动到另一个视图.到现在为止,我只是按 sergues 推送我的视图,这很容易用故事板实现.但是当我尝试返回我之前的视图时,将实现一个新的 ViewController,因此我存储在旧视图中的所有数据都丢失"了.
I'm trying to switch back from my UIViewController to my UITableViewController but apperendly it's not working the way I want it to.I did create my Interface with storyboards from the start, so I'm not really into moving from one View to another by code. Until now, I just pushed my Views per sergues which are easy to implement with storyboards. But when I tried moving back to my previous Views, a new ViewController will be implemented, so all my data I stored in the old one is "lost".
实际上我没有可以向您展示的代码(因为 sergues),但情况是:
Actually there is no code I could present you (because of the sergues) but the situation is:
->我在 UITableView 中有一个 MutableArray 存储东西.
->I got an MutableArray storing stuff in my UITableView.
->用户点击扫描按钮,扫描一个应该导入到我的阵列中的新项目.
->User taps the scan Button, scans a new Item which should be imported in my array.
->当试图推回我的 tableView 时,有一个新的控制器在等待我,不知道我存储在旧控制器中的数据.
->When trying to push back to my tableView there's a new Controller awating me, unaware of the data I stored in the old one.
那么我如何简单地移回我的旧控制器,防止一直创建一个新控制器?
So how do I simply move back to my old Controller preventing to create a new one all the time?
sergue-push 是否总是创建一个新的控制器?
Does a sergue-push always creates a new Controller?
(问题可能很简单,但我是这个东西的新手.尝试了搜索功能提供的一些结果,但没有一个奏效:( )
(Question may be simple, but I'm new to this stuff. Tried some results presented by the search function, but none of them worked :( )
/edit: 弹回问题已解决,但数组填充问题仍然存在.代码:
/edit: Popback problem has been solved but array filling problem still exists. Code:
GeneralSettings *sharedGS = [GeneralSettings sharedInstance];
sharedGS.strEAN = [[NSString alloc] initWithString:strCheckString];
[sharedGS.listArray insertObject:strCheckString atIndex:0];
NSLog(@"Anzahl der EAN-Codes: %d
Erster Code: %@
In Variable: %@", sharedGS.listArray.count, [sharedGS.listArray objectAtIndex:0],sharedGS.strEAN);
sharedGS.strEAN 中的数据(即83274572354")listArray 中的数据(空)
Data in sharedGS.strEAN ("83274572354" i.e.)Data in listArray (null)
推荐答案
你不会退缩.这将创建前一个控制器类的新实例.你弹回来.您可以通过两种方式实现.
You don't push back. That creates a new instance of the previous controller class. You pop back. You can accomplish that 2 ways.
1:当您想返回(弹出)到平板电脑视图控制器时,在代码中放入以下语句.
1: In code put in the following statement when you want to return (pop) to you tablet view controller.
[self.navigationController popViewControllerAnimated:YES];
2:如果你想在 storyboard 中实现,你需要实现以下自定义 segue 类:
2: If you want to do it in storyboard you need to implement the following custom segue class:
实施
// PopSegue.m
#import "PopSegue.h"
@implementation PopSegue
- (void) perform {
UIViewController *src = (UIViewController *) self.sourceViewController;
[src.navigationController popViewControllerAnimated:YES];
}
和标题
// PopSegue.h
#import <UIKit/UIKit.h>
@interface PopSegue : UIStoryboardSegue
@end
将此方法放在您的 UIViewController 中以将属性设置回您的 UITableViewController:
Place this method in your UIViewController to set a property back to your UITableViewController:
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:@"goBackToTableView"]) {
[[segue destinationViewController] set{whatEverProperyYouWantTo}: {valueOfPropertyToSet}];
}
}
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