Rust是否会将添加到矢量中的单个项目装箱?

问题描述

根据Rust文档:

据我了解，这意味着:

• Rust将在堆上分配足够的内存以连续存储类型T.
• 铁锈不会将它们放入矢量中时单独装箱.

换句话说，如果我向向量添加一些整数，而Vec将分配足够的存储空间来存储这些整数，那么它也不会将这些整数装箱.引入另一层间接.

我不确定如何用代码示例来说明或确认这一点，但会有所帮助.

解决方案

是，Vec<T>会将所有项目存储在连续的缓冲区中，而不是单独装箱. 文档指出:

请注意，也可以对向量进行切片，以获得&[T](切片).再次其文档确认这一点:

According to the Rust documentation:

As I understand this, it means that:

• Rust will allocate enough memory on the heap to store the type T in a contiguous fashion.
• Rust will not individually box the items as they are placed into the vector.

In other words, if I add a few integers to a vector, while the Vec will allocate enough storage to store those integers, it's not also going to box those integers; introducing another layer of indirection.

I'm not sure how I can illustrate or confirm this with code examples but any help is appreciated.

解决方案

Yes, Vec<T> will store all items in a contiguous buffer rather than boxing them individually. The documentation states:

Note that it is also possible to slice a vector, to get a &[T] (slice). Its documentation, again, confirms this:

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