我正在尝试打印我的char数组，但它只是打印数字为什么？

问题描述

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[])
{
int counter;
char car[3]={'a','b','c',};
counter = 0;
 while(counter < 3)
{

   printf("%d\n",car[counter]);
   counter++;
    }




	return 0;

What I have tried:

i have tried changing the values and trying different codes but nothing comes up it just gives me ramdon numbers on the output which i find annoying cuz the values are ABC

推荐答案

Quote：

printf（％d \ n，car [counter]）;

printf("%d\n",car[counter]);

to

printf("%c\n",car[counter]);

查看 []。



顺便说一下，你得到的数字不是随机的。它们是 []对应字符'a'，'b'，'c'。

Have a look at printf documentation[^].

By the way, the numbers you get are not random ones. They are the ASCII codes[^] corresponding to the characters 'a', 'b', 'c'.

printf("%c\n",car[counter]);

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