超时DefaultHttpClient

问题描述

限时删除！！

我在DefaultHttpClient如何工作超时。

I'm a little confused on how the timeouts in DefaultHttpClient work.

我使用这个code：

private DefaultHttpClient createHttpClient() {
        HttpParams my_httpParams = new BasicHttpParams();

        HttpConnectionParams.setConnectionTimeout(my_httpParams, 3000);
        HttpConnectionParams.setSoTimeout(my_httpParams, 15000);

        SchemeRegistry registry = new SchemeRegistry();
        registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
        ThreadSafeClientConnManager multiThreadedConnectionManager = new ThreadSafeClientConnManager(my_httpParams, registry);

        DefaultHttpClient httpclient = new DefaultHttpClient(multiThreadedConnectionManager, my_httpParams);

        return httpclient;
}

String url = "http://www.example.com";

DefaultHttpClient httpclient = createHttpClient();
HttpGet httpget = new HttpGet(url);

try {
    HttpResponse response = httpclient.execute(httpget);
    StatusLine statusLine = response.getStatusLine();
    mStatusCode = statusLine.getStatusCode();

    if (mStatusCode == 200){
        content = EntityUtils.toString(response.getEntity());
    }

} catch (ClientProtocolException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
} catch (IllegalStateException e){
    e.printStackTrace();
}

当第15秒钟过去了，并不是所有的数据已收到，一个会抛出异常，对不对？但在其上的方法？我认为这是 .execute（HTTPGET）方法，但一个只告诉我，它会抛出 ClientProtocolException 和 IOException异常。谁能帮我clearifying呢？

When 15 seconds have passed and not all data has been received, an exception will be thrown, right? But on which method? I thought it to be the .execute(httpget) method but that one only tells me it throws ClientProtocolException and IOException. Could anyone help me clearifying this?

推荐答案

它扔在异常的execute（）。 SocketTimeoutException 的母公司是 IOException异常。 catch块处理 IOException异常将能够赶上两个。

It does throw an exception on execute(). The parent of SocketTimeoutException is an IOException. A catch block handling IOException will be able to catch both.

尝试执行此code。

HttpParams my_httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(my_httpParams, 3000);
HttpConnectionParams.setSoTimeout(my_httpParams, 1);
DefaultHttpClient defaultHttpClient = new DefaultHttpClient(my_httpParams);
HttpGet httpGet = new HttpGet("http://google.com");
defaultHttpClient.execute(httpGet);

这导致了这个异常。

It results in this exception.

java.net.SocketTimeoutException: Read timed out
    at java.net.SocketInputStream.socketRead0(Native Method)
    at java.net.SocketInputStream.read(Unknown Source)
    ...
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:805)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:784)

您可以随时选择通过捕捉并处理 IOException异常后选择性地处理除外。

You can always choose to selectively process the exception by catching it and handling IOException later.

try
{
    // Your code
}
catch (SocketTimeoutException e)
{
    // handle timeouts
    e.printStackTrace();
}
catch (IOException e)
{
    // handle other IO exceptions
    e.printStackTrace();
}

这篇关于超时DefaultHttpClient的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！

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