根据第一个选择框选项填充第二个选择框

问题描述

我有这个选择，让我们称之为X，通过SELECT将数据库中的汽车品牌填充为选项。

I'm having this select, let's call it "X", that is populated with car brands as options from the database via a SELECT.

<select name="X">
<?php
$row = mysqli_query("SELECT * FROM brands");
while($row2 = mysqli_fetch_array($row))
echo '<option value="' . $row2['brandID'] . '">' . $row2['brandName'] . '</option>
?>
</select>

现在，我必须填写第二个选择，称为Y，其中包含品牌的型号选择

Now i have to populate the second select, called "Y", with the models specifics to a brand selected.

例如，如果在第一个选择框（X）中选择的选项是奥迪，我应该在第二个选择（Y）中具有以下选项： A4，A6，TT，TTs

For example, if the option that's selected in the first select box (X) is Audi i should have as options in the second select (Y) the following: A4,A6,TT,TTs

手动填充第二个选择框很简单，基本上与第一个只是使用不同的SQL请求相同的东西。 >

To populate the second select box manually is easy, basicaly the same thing as for the first just with a different SQL request.

$row = mysqli_query("SELECT modelName from modele WHERE brandName = '$brand'");

根据第一选择的选择，$品牌将有一个值。

Where $brand would have a value according to the first select's selection.

谢谢

推荐答案

Put an id in your <select name="X"> code like <select name="X" id ="X">

Put another select like <select name="Y" id="Y">. Which will be blank.

put this jquery in your page.

$("X").on("change",function(){
    var x_value=$("X").val();
    $.ajax({
        url:'ajax.php',
        data:{brand:x_value},
        type: 'post',
        success : function(resp){
            $("#Y").html(resp);
        },
        error : function(resp){}
    });
});

in your ajax.php add the query.

<?php
$row = mysqli_query("SELECT modelName from modele WHERE brandName =".$_POST['brand']);
while($row2 = mysqli_fetch_array($row))
    echo '<option value="' . $row2['modelId'] . '">' . $row2['modelName'] . '</option>
?>

希望它会工作。请告诉我需要什么。

Hopefully it will work. Please tell me if you need anything.

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