zmq错误码156384763的原因

问题描述

我正在使用 zmq req/rep 模式通信.实现非常简单，req 发送一些数据并等待 recv.代表接收数据，处理并回复.

I am using zmq req/rep pattern communication. The implementation is pretty simple, the req sends some data and waits on recv. The rep receives the data, process and reply back.

//REQ
zmq_connect
zmq_send
zmq_recv //blocking
zmq_close

//REP
zmq_bind
while(true) {
  while(data_received) {
    //miscellaneous process
    zmq_recv //non-blocking
      Print zmq_error_no if zmq_recv fails
  }
  zmq_send
}

在 REP 端，在 zmq_recv 超时期间 zmq_error_no 11 将被打印.但有时我会收到 156384763 号错误.谁能说出该错误的含义?

In the REP side, during zmq_recv timeout zmq_error_no 11 will be printed. But sometimes i am getting error no 156384763. could anyone tell the meaning for that error?

推荐答案

这是原生 ZeroMQ 错误 EFSM:

This is the native ZeroMQ error EFSM:

由于套接字未处于适当的状态，此时无法在此套接字上执行 zmq_send() 操作.在多个状态之间切换的套接字类型可能会出现此错误，例如 ZMQ_REP.

来源:zmq_send、zmq.h

这篇关于zmq错误码156384763的原因的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！