嗨Jeremy " Jeremy Yallop" < JE **** @ jdyallop.freeserve.co.uk>在消息中写道 news:sl ******************* @ maka.cl.cam.ac.uk ...Hi Jeremy"Jeremy Yallop" <je****@jdyallop.freeserve.co.uk> wrote in messagenews:sl*******************@maka.cl.cam.ac.uk... Joachim Schmitz写道: Joachim Schmitz wrote:声称符合标准(c89)的C编译器对以下内容发出错误是否合法:是。实际上,符合标准的编译器/有义务/诊断这个代码。 Is it legal for a C compiler that claims to be conforming to thestandard (c89) to issue an error on the following: Yes. In fact, a conforming compiler is /obliged/ to diagnose this code. char * foo(const char * s) const char * s; char *foo(const char *s) { const char *s; [...] [...]我会理解一个警告,但是出错? I''d understand a warning, but an error? 标准要求诊断和诊断。是为了某些违法行为而发出的。在发出这样的诊断之后,编译器没有义务继续翻译。 There''s no distinction between warnings and errors in C89: the standard requires that "diagnostics" are issued for certain violations. After such a diagnostic has been issued the compiler is under no obligation to continue translation. 谢谢, 好​​吧,不幸的是Samba代码充满了这些东西,我必须在所有地方插入 (char *)来编译... 如果允许编译器对此嗤之以鼻,这将是Samba的一个错误,我会 报告它。否则我会把它报告为对我们的c89的错误... Jeremy。Thanks,Well, unfortunaly the Samba code is full of such things and I have to insert(char *) all over the place to get it compiled...If a compiler is allowd to choke on this, it''d be a bug in Samba and I''llreport it as such. Otherwise I''d report it as a bug against our c89... Jeremy. 再见,JojoBye, Jojo Joachim Schmitz< no *********** @ hp.com>写道:Joachim Schmitz <no***********@hp.com> wrote:嗨伙计对于声称符合标准的C编译器(c89)是否合法,以便对以下内容发出错误: char * foo(const char * s) { const char * s; for(s = src; * s&&!(((unsigned char)s [0] )& 0x80); s ++) if(* s == c) return s; ... } 编译时遇到2个错误: error(212):返回值类型与函数类型不匹配 error(611) :类型为const char *的值不能分配给类型为char *的实体 我会理解一个警告,但是出错了吗? Hi folks Is it legal for a C compiler that claims to be conforming to the standard (c89) to issue an error on the following: char *foo(const char *s) { const char *s; for (s = src; *s && !(((unsigned char)s[0]) & 0x80); s++) if (*s == c) return s; ... } I get 2 errors when compiling this: error(212): return value type does not match the function type error(611): a value of type "const char *" cannot be assigned to an entity of type "char *" I''d understand a warning, but an error? 在这种情况下,编译器有义务发出诊断信息。是否 这是一个警告或错误是没有密切关系的标准 。 - Alex Monjushko(mo*******@hotmail.com)The compiler is obligated to emit a diagnostic in this case. Whetherit is a warning or an error is not germane as far as the standard isconcerned.--Alex Monjushko (mo*******@hotmail.com) 这篇关于char *与const char *的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云!
08-31 08:23