如何将十六进制字符串转换为UInt16?

问题描述

我有一个十六进制字符串d285，我想将其转换为UInt16，请指导我如何进行转换.我尝试过

I have a HEX string d285 and I want to convert it UInt16, please guide me how I can convert it. I tried this

let buffer = UInt16("\(UInt8(text, radix: 16)!)")
return Data(bytes: (buffer?.bigEndian.toBytes)!)

但是它不起作用

推荐答案

UInt16具有带有字符串和基数值的初始化器.可以用来从字符串创建UInt16.

UInt16 has an initializer that takes a string and radix value. This can be used to create UInt16 from string.

let hexString = "d285"
let hexToInt = UInt16(hexString, radix: 16) // prints 53893

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