Javascript datepicker排除周末，一系列日期&每周的特定日子

问题描述

我正在尝试排除周末，从我的datepicker开始每周的日期和星期一。这是我到目前为止：

I'm trying to exclude weekends, an array of dates and monday of every week from my datepicker. This is what I have so far:

var disableddates = ["12-21-2015", "12-24-2015", "1-4-2016", "1-5-2016"];
function DisableSpecificDates(date) {

  var m = date.getMonth();
  var d = date.getDate();
  var y = date.getFullYear();

  var currentdate = (m + 1) + '-' + d + '-' + y ;

  for (var i = 0; i < disableddates.length; i++) {

  if ($.inArray(currentdate, disableddates) != -1 ) {
      return [false];
    }
  }

  var weekend = $.datepicker.noWeekends(date);
  return [(weekend[0] || date.getDay() == 1)]; // I'm trying to disable Monday here

}

$(function() {
  $("#date").datepicker( {
    minDate: setMinDate,
    maxDate: "+2M",
    beforeShowDay: DisableSpecificDates
  });
});

具体日期（存储在 disableddates 数组）与周末一样排除在外，但星期一仍然可以选择 - 有谁知道我在哪里出错，还是其他解决方案？

The specific dates (stored in the disableddates array) are excluded, as are the weekends, but Monday is still selectable - does any one know where i'm going wrong, or an alternative solution to this?

推荐答案

所以如果我明白了，你只要星期二到星期五的日期。检查什么 $。datepicker.noWeekends（date）; ，如果它是一个工作日，它将返回1，如果是周末日期，则返回0。所以让我们检查你的代码：

So if I understood right you want just tuesday-friday dates. Checked what $.datepicker.noWeekends(date); does and it will return a 1 if it´s a weekday and 0 if it´s a weekend date. So let's check your code:

周末[0] || date.getDay（）== 1

如果周末[0] 是false ，这意味着 date.getDay（）== 0 或 == 6 （星期日或星期六）。但是对于 date.getDay（）== 1 ， weekend [0] 将永远是正确的。所以你总是允许星期一，因为 true || true == true

If weekend[0] is false, that means that date.getDay() == 0 or == 6 (sunday or saturday). But weekend[0] will always be true for date.getDay() == 1 . So you are always allowing monday, as true || true == true

你想要的是：

return [(weekend[0] && date.getDay() != 1)];

这意味着如果星期一星期不同于星期一

Which means allow it if it´s a week day different than monday

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