本文介绍了是否有一个内置函数可以将数字转换为任何基数的字符串?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想替换内部 match 语句并为所有值工作,直到字母表用完为止.我知道我可以自己写,但我想使用内置函数.

I want to replace the inner match statement and work for all values up to when the alphabet runs out. I know I can write it myself, but I want to use built-in functions.

fn convert(inp: u32, out: u32, numb: &String) -> Result<String, String> {
    match isize::from_str_radix(numb, inp) {
        Ok(a) => match out {
            2 => Ok(format!("{:b}", a)),
            8 => Ok(format!("{:o}", a)),
            16 => Ok(format!("{:x}", a)),
            10 => Ok(format!("{}", a)),
            0 | 1 => Err(format!("No base lower than 2!")),
            _ => Err(format!("printing in this base is not supported")),
        },
        Err(e) => Err(format!(
            "Could not convert {} to a number in base {}.
{:?}
",
            numb, inp, e
        )),
    }
}

推荐答案

如果你想获得更多的性能,你可以创建一个结构体并实现 DisplayDebug为它.这避免了分配 String.为了最大限度地进行过度设计,您还可以使用堆栈分配的数组来代替 Vec.

If you wanted to eke out a little more performance, you can create a struct and implement Display or Debug for it. This avoids allocating a String. For maximum over-engineering, you can also have a stack-allocated array instead of the Vec.

这是 Boiethios 的回答,应用了这些更改:

Here is Boiethios' answer with these changes applied:

struct Radix {
    x: i32,
    radix: u32,
}

impl Radix {
    fn new(x: i32, radix: u32) -> Result<Self, &'static str> {
        if radix < 2 || radix > 36 {
            Err("Unnsupported radix")
        } else {
            Ok(Self { x, radix })
        }
    }
}

use std::fmt;

impl fmt::Display for Radix {
    fn fmt(&self, f: &mut fmt::Formatter) -> fmt::Result {
        let mut x = self.x;
        // Good for binary formatting of `u128`s
        let mut result = [''; 128];
        let mut used = 0;
        let negative = x < 0;
        if negative {
            x*=-1;
        }
        let mut x = x as u32;
        loop {
            let m = x % self.radix;
            x /= self.radix;

            result[used] = std::char::from_digit(m, self.radix).unwrap();
            used += 1;

            if x == 0 {
                break;
            }
        }

        if negative {
            write!(f, "-")?;
        }

        for c in result[..used].iter().rev() {
            write!(f, "{}", c)?;
        }

        Ok(())
    }
}

fn main() {
    assert_eq!(Radix::new(1234, 10).to_string(), "1234");
    assert_eq!(Radix::new(1000, 10).to_string(), "1000");
    assert_eq!(Radix::new(0, 10).to_string(), "0");
}

这仍然可以通过以下方式进行优化:

This could still be optimized by:

  • 创建一个 ASCII 数组而不是 char 数组
  • 不对数组进行零初始化

由于这些途径需要 unsafe 或像 arraybuf 这样的外部 crate,我没有包括他们.您可以在 标准库的内部实现细节.

Since these avenues require unsafe or an external crate like arraybuf, I have not included them. You can see sample code in internal implementation details of the standard library.

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08-23 06:30