选择一个有吸引力的线性比例为图形的Y轴 - 更多

问题描述

继：http://stackoverflow.com/questions/326679/choosing-an-attractive-linear-scale-for-a-graphs-y-axis

我相信这部分的问题没有得到回答，但似乎我不能评论或扩展的问题，所以我已经创建了一个新的

 值-100，0，100 5蜱：
 

1. 下限= -100
2. 上限= 100
3. 范围= 100--100 = 200
4. 在刻度范围= 40
   1. 除以10 ^ 2为0.4，转化为0.4，这给40（10 ^ 2相乘）。
5. 在新下界= 40 *圆（-100/40）= -80
6. 在新的上限= 40 *轮（1 +100 / 40）= 120

或

1. 在新下界= 40 *楼（-100/40）= -120
2. 在新的上限= 40 *地板（1 +100 / 40）= 120

现在的范围已经在40各增加至240（一个额外的滴答！），用5蜱。这将需要6个步骤，以填补新的范围！

解决方案？

解决方案

我用下面的code。它产生于人类的观众很好地间隔的步骤和迎合穿过零范围。

公共静态类AxisUtil{    公共静态浮动CalculateStepSize（浮动范围，浮动targetSteps）    {        //计算在步长的初始猜测        浮tempStep =范围/ targetSteps;        //获取步长的大小        浮磁=（浮点）Math.Floor（Math.Log10（tempStep））;        浮动magPow =（浮点）Math.Pow（10，MAG）;        //计算新的步长的最显著位        浮magMsd =（int）的（tempStep / magPow + 0.5）;        //促进来自MSD 1，2，或5        如果（magMsd＆GT; 5.0）            magMsd = 10.0f;        否则，如果（magMsd＆GT; 2.0）            magMsd = 5.0F;        否则，如果（magMsd＆GT; 1.0）            magMsd = 2.0f;        返回magMsd * magPow;    }}

Further to: http://stackoverflow.com/questions/326679/choosing-an-attractive-linear-scale-for-a-graphs-y-axis

I believe this part of the question was not answered but it seems I can't comment or extend that question so I've created a new one

Values -100, 0, 100 with 5 ticks:

1. lower bound = -100
2. upper bound = 100
3. range = 100--100 = 200
4. tick range = 40
   1. Divide by 10^2 for 0.4, translates to 0.4, which gives (multiplied by 10^2) 40.

5. new lower bound = 40 * round(-100/40) = -80
6. new upper bound = 40 * round(1+100/40) = 120

or

1. new lower bound = 40 * floor(-100/40) = -120
2. new upper bound = 40 * floor(1+100/40) = 120

Now the range has been increased to 240 (an extra tick!), with 5 ticks at 40 each.it will take 6 steps to fill the new range!

Solution?

解决方案

I use the following code. It produces nicely-spaced steps for human viewers and caters for ranges that pass through zero.

public static class AxisUtil
{
    public static float CalculateStepSize(float range, float targetSteps)
    {
        // calculate an initial guess at step size
        float tempStep = range/targetSteps;

        // get the magnitude of the step size
        float mag = (float)Math.Floor(Math.Log10(tempStep));
        float magPow = (float)Math.Pow(10, mag);

        // calculate most significant digit of the new step size
        float magMsd = (int)(tempStep/magPow + 0.5);

        // promote the MSD to either 1, 2, or 5
        if (magMsd > 5.0)
            magMsd = 10.0f;
        else if (magMsd > 2.0)
            magMsd = 5.0f;
        else if (magMsd > 1.0)
            magMsd = 2.0f;

        return magMsd*magPow;
    }
}

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