NodeJS Express-分别处理404(未找到)和405(不允许使用方法)

问题描述

我正试图找到一种方法来处理我的Express应用程序中的404和405状态代码，但要分开处理它们.

I'm trying to find a way to handle both 404 and 405 status code in my Express application, but handling them separatedely.

例如:我有一个类似以下的路由器:

e.g.: I have a router like the following:

// Add routes for every path we define here.
server.use('/', require('./indexRoutes'))
server.use('/account', require('./accountRoutes'))

// Handling route errors.
server.all('*', (request, response) => 
    response.status(404).send('Invalid route (not found).')
)

但是，server.all方法将处理无效的路由或无效的HTTP动词.有没有一种方法可以分开对待它们，以便为每种情况发送不同的状态，内容和所有内容?

However, either invalid routes or invalid HTTP verbs are being treated by the server.all method. Is there a way to treat them separatedely, in order to send different status, content and everything for each scenario?

谢谢大家！

推荐答案

我想到的第一件事是，在声明所有有用的路径后，为要响应的405路径声明每个错误.例如，在您的accountRoutes中:

First thing that come to my mind is to declare for each path you want to response 405 error after you declare all your useful paths.For example, in your accountRoutes:

server.get('/account', ....);
server.post('/account', ...);
server.all('/account', (req, res, next) => {
   res.status(405).send('Method not allowed');
});

如果您收到/account路径的get或post，它将被您的方法处理.其他方法将以405代码作为响应.

If you receive a get or post to the /account path it will be treated with your method. Other methods will be responded with 405 code.

未实现Express的路径会默认发送404代码，我认为您无需实现

Paths not implemented express will send a 404 code by default, I think you don't need to implement it

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