问题描述
我认为operator []（）成员函数无法正常工作，是吗？
其他人都知道如何制作模板来制作二维数组来自
std :: vectors ???我想使用普通的数组[ROW] [COL]语法。
http://groups.google.com/group/comp....092f0f6c9bf13a
I think that the operator[]() member function does not work correctly, does
anyone else know how to make a template for making two dimensional arrays from
std::vectors ??? I want to use normal Array[ROW][COL] Syntax.
推荐答案
在发布的代码中（您可以包括）：
w_elem_type * operator []（t_Size i_index）
{
return& （m_data [i_index * m_rows]）;
}
''i_index * m_rows'' - 对我来说似乎有点可疑。现在已经很晚了
我不会花太多时间考虑它，但我认为
''i_index / m_rows''会更正确，但我可能错了。在纸上画一个
3x3矩阵并进行数学计算。
-
Erik Wikstr？m
In the code posted (which you could have included):
w_elem_type * operator[]( t_Size i_index )
{
return & ( m_data[ i_index * m_rows ] );
}
The ''i_index * m_rows''-part seems kind of fishy to me. It''s quite late
right now and I wont spend time thinking much about it, but I think that
''i_index / m_rows'' would be more correct, but I might be wrong. Draw a
3x3 matrix on paper and do the math.
--
Erik Wikstr?m
在发布的代码中（您可以包括）：
w_elem_type * operator []（t_Size i_index）
{
return& （m_data [i_index * m_rows]）;
}
''i_index * m_rows'' - 对我来说似乎有点可疑。现在已经很晚了
我不会花太多时间考虑它，但我认为''i_index /
m_rows''会更正确，但我可能错了。在
纸上画一个3x3矩阵并做数学运算。
-
Erik Wikstr？m
In the code posted (which you could have included):
w_elem_type * operator[]( t_Size i_index )
{
return & ( m_data[ i_index * m_rows ] );
}
The ''i_index * m_rows''-part seems kind of fishy to me. It''s quite late right
now and I wont spend time thinking much about it, but I think that ''i_index /
m_rows'' would be more correct, but I might be wrong. Draw a 3x3 matrix on
paper and do the math.
--
Erik Wikstr?m
我已将所有内容部分转换为Array [ROW] [COL]顺序。我发现
我需要将上述功能转换为
return& （m_data [i_index * m_columns]）;
我在发布此
消息后一分钟内发现了我的问题的解决方案。我链接的代码可能仍然正确。
感谢您的帮助。
I had partially converted everything over to Array[ROW][COL] order. I discovered
that I needed to convert the above function to
return & ( m_data[ i_index * m_columns ] );
I discovered this solution to my problem within a minute after I posted this
message. The code that I had linked to may still be correct.
Thanks for your help.
为什么？
Why?
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