问题描述
大家好，
我还在学习C ++，所以我不确定我要做的是
。她是一个简单的例子：
char Test =''L'';
cout<< 测试字符为十进制： << dec<<测试<< endl;
在上面的cout语句中，我希望它会显示76，即L字符的
十进制值。相反，它显示了L.是否有使用cout来显示价值的方式？
我知道我可以用printf完成这个，但是想要看看cout
也可以做到。提前致谢。
查理
Hello everyone,
I am still learning C++, so I''m not sure what I''m trying to do is
possible. Her is a simplified example:
char Test = ''L'';
cout << "Test Char as decimal: " << dec << Test << endl;
In the above cout statement, I was hoping it would show 76, the
decimal value of the L character. Instead, it displays an L. Is there
a way to use cout to show the value?
I know I can accomplish this with printf, but wanted to see if cout
could also do it. Thanks in advance.
Charlie
推荐答案
cout<< static_cast< int>（测试）<<结束;
-
Unforgiven
cout << static_cast<int>(Test) << endl;
--
Unforgiven
cout<< static_cast< int>（测试）<<结束;
-
Unforgiven
cout << static_cast<int>(Test) << endl;
--
Unforgiven
cout<< static_cast< int>（测试）<< endl;
cout << static_cast<int>(Test) << endl;
或者，
cout<< int（测试）<< endl;
Or,
cout << int( Test ) << endl;
这篇关于如何使用cout显示char的十进制值？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！