问题描述
我有两个向量定义开始(从)索引和结束(到)索引:
I have two vectors which define start (from) indices and finish (to) indices:
Start = c(1, 10, 20)
Finish = c(9, 19, 30)
我想沿着两个向量创建一个所有 Start:Finish
序列的列表,即生成序列 Start[1]:Finish[1]
(Start[1]:Finish[1]
>1:9);Start[2]:Finish[2]
,依此类推.
I want to create a list of all Start:Finish
sequences along the two vectors, i.e. generate the sequences Start[1]:Finish[1]
(1:9
); Start[2]:Finish[2]
, and so on.
## [[1]]
## [1] 1 2 3 4 5 6 7 8 9
##
## [[2]]
## [1] 10 11 12 13 14 15 16 17 18 19
##
## [[3]]
## [1] 20 21 22 23 24 25 26 27 28 29 30
最好采用某种矢量化方式.'Start' 向量中的值将始终大于 'Finish' 向量中的相应元素.
Preferably in some vectorized way. The values in 'Start' vector will always be larger than the corresponding elements in 'Finish' vector.
推荐答案
只需使用mapply
:
Start = c(1,10,20)
Finish = c(9,19,30)
mapply(":", Start, Finish)
## [[1]]
## [1] 1 2 3 4 5 6 7 8 9
##
## [[2]]
## [1] 10 11 12 13 14 15 16 17 18 19
##
## [[3]]
## [1] 20 21 22 23 24 25 26 27 28 29 30
##
当然,您也可以使用 Vectorize
,但这只是 mapply
的包装器.但是,Vectorize
不能与原始函数一起使用,因此您必须指定 seq.default
而不是 seq
或 seq.int
.
You could, of course, also use Vectorize
, but that's just a wrapper for mapply
. However, Vectorize
cannot be used with primitive functions, so you'll have to specify seq.default
rather than seq
, or seq.int
.
示例:
Vectorize(seq.default)(Start, Finish)
## [[1]]
## [1] 1 2 3 4 5 6 7 8 9
##
## [[2]]
## [1] 10 11 12 13 14 15 16 17 18 19
##
## [[3]]
## [1] 20 21 22 23 24 25 26 27 28 29 30
##
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