本文介绍了根据另一个文件作为匹配条件过滤文件条目的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
bash和脚本编写的真正初学者，如果对您来说这是一个非常基本的问题，请对不起.
Really beginner of bash and scripting so sorry if it is very basic question to You.
我有大约1百万行的file1，每行包含两个字段.我有〜270.000行的file2，每行有一个条目.与file1字段1相同.
I have file1 with ~1 million rows contain two fields in every row.I have file2 with ~270.000 rows, single entry in every rows. It is common with file1 field 1.
目标是基于file2条目从file1(保留filed1和field2条目)中筛选出一个列表.
The goal is to have a filtered list from the file1 (keep the filed1 and field2 entries) based on file2 entries.
示例:
file1
1 A
2 B
3 C
4 C
5 D
6 A
7 G
8 K
122 F
.
.
56677 A
.
7272727272 A
1.000.000 A
File2:
1
2
3
9
122
56677
7272727272
我要基于file2过滤第一列，输出应如下所示:
I want filter the first column based on file2 and output should be like this:
1 A
2 B
3 C
122 F
56677 A
7272727272 A
推荐答案
如果提供了预期的输出，请尝试以下行:
try this line, if it gave expected output:
grep -Fwf file2 file1
或
awk 'NR==FNR{a[$0]=1;next}a[$1]' file2 file1
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