我们如何使用 cuPrintf()?

问题描述

我们必须做什么才能使用 cuPrintf()?(设备计算能力 1.2，Ubuntu 12)我找不到cuPrintf.cu"和cudaPrintf.cuh"，所以我下载了它们的代码并包含它们:

What do we have to do to use cuPrintf()? (device compute capability 1.2, Ubuntu 12) I couldn't find "cuPrintf.cu" and "cudaPrintf.cuh", so i downloaded their code and include them:

#include "cuPrintf.cuh"
#include "cuPrintf.cu"

顺便说一句，这是其余的代码:

By the way this is the rest of the code:

__global__ void hello_kernel (float f) {
printf ("Thread number %d. f = %d
", threadIdx.x, f);
}

    int main () {
    dim3 gridSize = dim3 (1);
    dim3 blockSize = dim3 (16);
    cudaPrintfInit ();
    hello_kernel <<< gridSize, blockSize >>> (1.2345f);
    cudaPrintfDisplay (stdout, true);
    cudaPrintfEnd ();
    return (0);
}

但是nvcc还是报错:

But nvcc still gives a mistake:

max@max-Lenovo-G560:~/CUDA/matrixMult$ nvcc printfTest.cu -o printfTest

printfTest.cu(5): error: calling a __host__ function("printf") from a __global__
function("hello_kernel") is not allowed

谢谢！

推荐答案

在你的内核中而不是这个:

In your kernel instead of this:

printf ("Thread number %d. f = %d
", threadIdx.x, f);

你应该这样做:

cuPrintf ("Thread number %d. f = %d
", threadIdx.x, f);

除此之外，我相信您的代码是正确的(它适用于我).

Other than that, I believe your code is correct (it works for me).

此SO question/answer提供了有关正确使用 cuPrintf 的更多提示.

This SO question/answer gives more tips about using cuPrintf properly.

这篇关于我们如何使用 cuPrintf()?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！