如何通过单击文件从上下文菜单接收命令？

问题描述

这是在指定文件的上下文菜单中创建项目的func。

如何获取被单击的文件路径？谢谢。

Here is the func that create item in context menu of specified file.
How to get path of file, which was clicked? Thanks.

using Microsoft.Win32;
//Extension - Extension of the file (.zip, .txt etc.)
//MenuName - Name for the menu item (Play, Open etc.)
//MenuDescription - The actual text that will be shown
//MenuCommand - Path to executable
private bool AddContextMenuItem(string Extension,
  string MenuName, string MenuDescription, string MenuCommand)
{
  bool ret = false;
  RegistryKey rkey =
    Registry.ClassesRoot.OpenSubKey(Extension);
  if(rkey != null)
  {
    string extstring = rkey.GetValue("").ToString();
    rkey.Close();
    if( extstring != null )
    {
      if( extstring.Length > 0 )
      {
        rkey = Registry.ClassesRoot.OpenSubKey(
          extstring,true);
        if(rkey != null)
        {
          string strkey = "shell\\" + MenuName + "\\command";
          RegistryKey subky = rkey.CreateSubKey(strkey);
          if(subky != null)
          {
            subky.SetValue("",MenuCommand);
            subky.Close();
            subky = rkey.OpenSubKey("shell\\" +
              MenuName, true);
            if(subky != null)
            {
              subky.SetValue("",MenuDescription);
              subky.Close();
            }
            ret = true;
          }
          rkey.Close();
        }
      }
    }
  }
  return ret;
}

推荐答案

if(subky != null)
{
   subky.SetValue("",MenuCommand + " \"%1\");
   ...
}

％1 会给你选择的文件名

The "%1" will give you the filename which was selected

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