Yii:如何使用另一个模型数据填充 Select 输入?

问题描述

我正在玩一个小应用程序以学习使用 Yii.

我创建了一个带有 2 个模型/表的小型 web 应用程序:项目和任务.(一对多关系，在模型类中正确配置).

我现在正在尝试自定义任务/创建"视图，将文本输入字段替换为一个提供可用项目列表的选择框.

我打开了表单视图并尝试了这个:

<?php echo $form->labelEx($model,'project_id');?><?php echo $form->textField($model,'project_id');?><?php//我的黑客从这里开始$projects = Project::model()->findAll();$list = CHtml::listData($projects, 'id', 'name');echo $form->listBox($model,'project_id','', $list);?>//我的 hack 到此结束<?php echo $form->error($model,'project_id');?>

但它不断抛出警告或错误(例如为foreach()提供的无效参数，并且绝对不起作用.我不明白我做错了什么.你能帮忙吗??

解决方案

你的论点不合理(应该是):

$frameworks = Framework::model()->findAll();$list = CHtml::listData($frameworks, 'id', 'name');echo $form->listBox($model,'framework_id', $list,array());

查看文档

I'm playing around with a small app in order to learn to use Yii.

I've created a small webapp with 2 models / tables: Projects and tasks. (1-to-many relationship, properly configured in the model classes).

I'm now trying to customize the Task/create view, replacing the text input field with a select box proposing the list of available projects.

I opened the form view and tried this:

<div class="row">
    <?php echo $form->labelEx($model,'project_id'); ?>
    <?php echo $form->textField($model,'project_id'); ?>
    <?php
// my hack starts here
    $projects = Project::model()->findAll();
    $list = CHtml::listData($projects, 'id', 'name');
    echo $form->listBox($model,'project_id','', $list); ?>

// my hack ends here
    <?php echo $form->error($model,'project_id'); ?>
</div>

But it keeps throwing warnings or error (such as Invalid argument supplied for foreach(), and definitely does not work. I'm failing to understand what i'm doing wrong. Can you help ?

解决方案

Your arguments are not in order (it should be):

$frameworks = Framework::model()->findAll();
$list = CHtml::listData($frameworks, 'id', 'name');
echo $form->listBox($model,'framework_id', $list,array());

Check the documentation

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