问题描述
尝试签署提交时出现此错误:
I'm getting this error when trying to sign a commit:
git commit -S -m "test"
gpg: skipped "EF617ACA9EC3XXXX": No secret key
gpg: signing failed: No secret key
error: gpg failed to sign the data
fatal: failed to write commit object
这是gpg --list-secret-keys --keyid-format LONG的输出
This is the output of gpg --list-secret-keys --keyid-format LONG
钥匙在那儿
sec rsa4096/EF617ACA9EC3XXXX 2020-05-17 [SC] [expires: 2022-05-17]
AD68154000A712DCD161D826EF617ACA9EC3XXXX
uid [ultimate] name <[email protected]>
这是具有相同键的git config
And this is git config with the same key
user.signingkey=EF617ACA9EC3XXXX
[email protected]
你知道怎么了吗?
推荐答案
首先检查 git config gpg.program 来查看这是 gpg 还是 gpg2 (如在此处).
Check first the git config gpg.program to see if this is gpg or gpg2 (as in here).
然后输入 where gpg 和 where gpg2 来检查GPG程序考虑的路径.
And type where gpg nd where gpg2 to check which path is considered for the GPG program.
我建议将 gpg.program 设置为 gpg2 ，然后复制您的 gpg.exe (假设其版本为2.x)到 gpg2.exe
I suggested to set gpg.program to gpg2, and copy your gpg.exe (assuming its version is a 2.x) to gpg2.exe
这应该强制Git/GPG充当gpg2.
That should force Git/GPG to act as gpg2.
这篇关于“没有秘密密钥"在Windows上签名git commit时出错的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！