本文介绍了在 PyQt PushButton 单击期间发送附加变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我是 Python 和 PyQt 的新手,这是我的第一个应用程序.当前,当单击按钮时,toggleLED() 检查 self.LedOn 以决定是否打开 LED.

I'm new to Python and PyQt and this is my first application. Currently when a button is clicked, toggleLED() checks self.LedOn to decide whether to turn an LED on.

class Screen(QWidget):

    def initUI(self):
        self.LedOn = 0

        btn = QPushButton('Off', self)
        btn.setCheckable(True)
        btn.clicked.connect(self.toggleLED)


    def toggleLED(self, pressed):

        source = self.sender()

        if self.LedOn:
            source.setText('Off')
            source.LedOn = 0
            self.serial.write('L')
        else:           
            source.setText('On')
            source.LedOn = 1
            self.serial.write('H')

问题:现在如果我们想要控制多个 LED 并记住它们各自的切换状态,最佳做法是什么?

Problem: Now if we want to control multiple LEDs and remember their individual toggle state, what is the best practice?

我似乎也无法使用 btn.clicked.connect(self.toggleLED(btnNumber))

class Screen(QWidget):

    def initUI(self):

        btn1 = QPushButton('Off', self)
        btn1.setCheckable(True)
        btn1.LedOn= 0
        btn1.clicked.connect(selftoggleLED(1))

        btn2 = QPushButton('Off', self)
        btn2.setCheckable(True)
        btn2.LedOn= 0
        btn2.clicked.connect(selftoggleLED(2))


    def toggleLED(self, pressed, value):

        source = self.sender()

        if self.LedOn:
            source.setText('Off')
            self.serial.write(value)
            self.serial.write('L')
        else:           
            source.setText('On')
            self.serial.write(value)
            self.serial.write('H')

推荐答案

你可以使用partial:

from functools import partial

btn1.clicked.connect(partial(self.toggleLED, 1))

这允许您将多个参数传递给一个函数.

This allows you to pass multiple arguments to a function.

这篇关于在 PyQt PushButton 单击期间发送附加变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-30 17:48