本文介绍了将唯一的ID添加到数字列表-VBA的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个数字列表(50,000+),我需要在每个唯一组的末尾添加一个ID.ID的格式为-###".
I have a list of numbers (50,000+) and I need to add a Id to the end of each unique group. The Id is in a format of "-###".
151022
151022
151020
150922
150715
150911
151014
151021
151020
151019
151019
151019
151020
我需要像这样打印
151022-001
151022-002
151020-001
150922-001
150715-001
150911-001
151014-001
151021-001
151020-002
151019-001
151019-002
151019-003
151020-002
我目前拥有找到并稍加修改的这段代码.如果我可以让它开始在-002处计算唯一值,那么我相信这会解决它.
I currently have this code that I found and modified slightly. If I could get it to start counting unique values at -002 then I believe that would solve it.
Option Explicit
Sub test()
Dim uniqueCounter As New Scripting.Dictionary
Dim counter As Long
Dim rowCount As Long
Dim identifer As String
rowCount = ActiveCell.CurrentRegion.Rows.Count 'Whatever code you want to put in to calculate the last row
For counter = 1 To rowCount
identifer = Sheet1.Cells(counter, 1) 'Put whatever number of combination of cells which the row unique here (maybe it's just the one)
If uniqueCounter.Exists(identifer) Then
uniqueCounter(identifer) = CLng(uniqueCounter(CStr(Sheet1.Cells(counter, 1)))) + 1
Sheet1.Cells(counter, 2) = identifer & "-00" & uniqueCounter(CStr(Sheet1.Cells(counter, 1)))
Else
uniqueCounter.Add identifer, "0"
Sheet1.Cells(counter, 2) = identifer
End If
Next counter
End Sub
当前显示的内容:
151022 151022
151022 151022-001
151020 151020
150922 150922
150715 150715
150911 150911
151014 151014
151021 151021
151020 151020-001
151019 151019
151019 151019-001
151019 151019-002
151020 151020-002
谢谢所有!
推荐答案
我知道您要求使用vba,但是一个简单的公式将为您提供所需的输出.
I know you asked for vba, but a simple formula will give you the desired output.
在B1中放:
=A1& "-" &TEXT(COUNTIF($A$1:A1,A1),"000")
并复制数据范围.
如果要在vba中使用它;我会做这样的事情:
If you want it in vba; I would do something like this:
Sub test2()
Dim rng As Range
Dim rngcnt As Range
Dim firstrow As Long
Dim lastrow As Long
Dim columnNumber As Long
Dim ws As Worksheet
Set ws = Worksheets("Sheet15") 'change to your sheet
firstrow = 1 'change to your first row of data
columnNumber = 1 'change to the column number
With ws
lastrow = .Cells(.Rows.Count, columnNumber).End(xlUp).Row
For i = firstrow To lastrow
.Cells(i, columnNumber + 1) = .Cells(i, columnNumber) & "-" & Format(Application.WorksheetFunction.CountIf(.Range(.Cells(firstrow, columnNumber), .Cells(i, columnNumber)), .Cells(i, columnNumber)), "000")
Next i
End With
End Sub
与上述公式的作用相同.
Which effectively does the same as the above formula.
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