本文介绍了如何解析web服务和使用POST方法在android系统发布的数据？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
=一个JSONObjects {
PROJID：78，
UID：1，
EMAILID：test@yahoo.com
ProjectInviterFQAnswer：[{
slno：1，
答案：A1，
序：1
标记：F
}，{
slno：2，
答案：A1，
序：2
标记：F
}，{
slno：1，
答案：A1，
序：2
旗帜：Q
}
]
};
我上面的web服务，现在我想将数据发布此WebService在关键的答案。我如何解析和投入答案我的钥匙串阵？
我的code如下。但它给响应，出现了一个错误。
@覆盖
保护字符串doInBackground（字符串的URL ...）{
HttpClient的HttpClient的=新DefaultHttpClient（）;
HttpContext的背景下=新BasicHttpContext（）;
HttpPost httpPost =新HttpPost（URL）;
JSONObject的JSON =新的JSONObject（）;
httpPost.setHeader（内容类型，
应用/ JSON的;字符集= UTF-8）; 尝试{ //json.put(\"EmailID\",\"test@yahoo.com）;
//json.put(\"ProjID\",\"78）;
//json.put(\"UID，1）;
//json.put(\"ProjectInviterFQAnswer，对象）;
StringEntity stringEntity =新StringEntity（json.toString（））;
InputStream的流=新
ByteArrayInputStream进行（json.toString（）的getBytes（UTF-8）。）;
httpPost.setEntity（新StringEntity（json.toString（）））;
HTT presponse HTT presponse = httpClient.execute（httpPost，背景）;
读者的BufferedReader =新的BufferedReader（新的InputStreamReader（HTT presponse.getEntity（）的getContent（），UTF-8））;
RES = reader.readLine（）;
RESP = res.toString（）;
Log.e（响应WEBSER的：RESP）;
}赶上（UnsupportedEncodingException五）{
// TODO自动生成catch块
e.printStackTrace（）;
}赶上（ClientProtocolException E）{
// TODO自动生成catch块
e.printStackTrace（）;
}赶上（IOException异常五）{
// TODO自动生成catch块
e.printStackTrace（）;
} 返回水库;
解决方案
以一个的ArrayList 的的NameValuePair 为例如的ArrayList＆LT;＆的NameValuePair GT; postParameters =新的ArrayList＆LT;＆的NameValuePair GT;（）;
然后添加您的paramters在接听键如下：
postParameters.add（新BasicNameValuePair（答案，
你的价值））;
串响应=无效;
尝试{
响应= CustomHttpClient
.executeHttpPost（
您的网址，postParameters）;`
CustomHTTPClientmethod
公共类CustomHttpClient {/ **所花费的时间为我们的客户超时* /
公共静态最终诠释HTTP_TIMEOUT = 30 * 1000; //毫秒
/ **我们的HttpClient单实例* /
私有静态HttpClient的mHttpClient;/ **
*获取我们的HttpClient我们对象的单个实例。
*
返回：一个HttpClient的对象，连接参数设置
* /私有静态HttpClient的getHttpClient（）{ 如果（mHttpClient == NULL）{
mHttpClient =新DefaultHttpClient（）; 最终的HttpParams PARAMS = mHttpClient.getParams（）;
HttpConnectionParams.setConnectionTimeout（参数，可以HTTP_TIMEOUT）;
HttpConnectionParams.setSoTimeout（参数，可以HTTP_TIMEOUT）;
ConnManagerParams.setTimeout（参数，可以HTTP_TIMEOUT）;
} 返回mHttpClient;
}/ **
*执行一个HTTP POST请求与指定指定的网址
*参数。
*
* @参数网址
*该网址张贴请求
* @参数postParameters
*参数通过发送请求
返回：请求的结果
* @throws异常
* /公共静态字符串executeHttpPost（字符串URL，
ArrayList的＆LT;＆的NameValuePair GT; postParameters）抛出异常{ 在的BufferedReader = NULL; 尝试{ HttpClient的客户= getHttpClient（）; HttpPost要求=新HttpPost（URL）; UrlEn codedFormEntity formEntity =新UrlEn codedFormEntity（ postParameters）; request.setEntity（formEntity）; HTT presponse响应= client.execute（请求）; 在=新的BufferedReader（新的InputStreamReader（response.getEntity（） .getContent（）））; StringBuffer的SB =新的StringBuffer（）; 串线=; 串NL = System.getProperty（line.separator）; 而（（行= in.readLine（））！= NULL）{ sb.append（行+ NL）; } 附寄（）; 字符串结果= sb.toString（）; 返回结果; } {最后 如果（在！= NULL）{ 尝试{ 附寄（）; }赶上（IOException异常五）{ Log.e（log_tag，错误转换结果+ e.toString（））; e.printStackTrace（）; } } }}
}
希望这可以解决你所要求的。
jsonObjects = {
"ProjID": "78",
"Uid": "1",
"EmailID": "test@yahoo.com",
"ProjectInviterFQAnswer": [{
"slno": "1",
"Answer": "a1",
"order": "1",
"flag": "F"
}, {
"slno": "2",
"Answer": "a1",
"order": "2",
"flag": "F"
}, {
"slno": "1",
"Answer": "a1",
"order": "2",
"flag": "Q"
}
]
};
I have the above webservice, and now I want to post data to this webservice in the key "answer". How can I parse and put my array string in "answer" key?
my code is as follows. but it gives response as An error has occured..
@Override
protected String doInBackground(String... urls) {
HttpClient httpClient= new DefaultHttpClient();
HttpContext context=new BasicHttpContext();
HttpPost httpPost=new HttpPost(url);
JSONObject json=new JSONObject();
httpPost.setHeader("Content-type",
"application/json; charset=UTF-8");
try {
//json.put("EmailID","test@yahoo.com");
//json.put("ProjID","78");
//json.put("UID", "1");
//json.put("ProjectInviterFQAnswer", "Object");
StringEntity stringEntity = new StringEntity(json.toString());
InputStream stream= new
ByteArrayInputStream(json.toString().getBytes("UTF-8"));
httpPost.setEntity(new StringEntity(json.toString()));
HttpResponse httpResponse= httpClient.execute(httpPost,context);
BufferedReader reader= new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent(),"UTF-8"));
res= reader.readLine();
resp=res.toString();
Log.e("RESPONSE OF WEBSER:", resp);
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return res;
解决方案 Take an ArrayList of NameValuePair for e.gArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
then add your paramters in the answer key as follows
postParameters.add(new BasicNameValuePair("answer",
"Your value"));
String response = null;
try {
response = CustomHttpClient
.executeHttpPost(
"Your Url", postParameters);`
CustomHTTPClientmethod
public class CustomHttpClient {
/** The time it takes for our client to timeout */
public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds
/** Single instance of our HttpClient */
private static HttpClient mHttpClient;
/**
* Get our single instance of our HttpClient object.
*
* @return an HttpClient object with connection parameters set
*/
private static HttpClient getHttpClient() {
if (mHttpClient == null) {
mHttpClient = new DefaultHttpClient();
final HttpParams params = mHttpClient.getParams();
HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT);
HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT);
ConnManagerParams.setTimeout(params, HTTP_TIMEOUT);
}
return mHttpClient;
}
/**
* Performs an HTTP Post request to the specified url with the specified
* parameters.
*
* @param url
* The web address to post the request to
* @param postParameters
* The parameters to send via the request
* @return The result of the request
* @throws Exception
*/
public static String executeHttpPost(String url,
ArrayList<NameValuePair> postParameters) throws Exception {
BufferedReader in = null;
try {
HttpClient client = getHttpClient();
HttpPost request = new HttpPost(url);
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(
postParameters);
request.setEntity(formEntity);
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity()
.getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
String result = sb.toString();
return result;
} finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
Log.e("log_tag", "Error converting result " + e.toString());
e.printStackTrace();
}
}
}
}
}
Hope this solves what you are asking for ..
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