printf ptr:可以消除开头的0x吗?

问题描述

Linux printf将％p参数呈现为带有前导0x的十六进制数字.有没有办法使它不打印0x?(需要同时在32位和64位上工作.)

The Linux printf renders %p arguments as hex digits with a leading 0x. Is there a way to make it not print the 0x? (Needs to work on both 32 and 64 bit.)

推荐答案

您可以将 uintptr_t 的格式说明符用于< inttypes.h> :

You can use the format specifier for uintptr_t from <inttypes.h>:

#include <inttypes.h>
[...]
printf("%"PRIxPTR"\n", (uintptr_t) p);

对于 uintptr_t 类型，它的作用类似于％x ，它是一种整数类型，能够从/向任何指针类型进行往返转换.

This works like %x for the uintptr_t type, which is an integer type capable of roundtrip conversion from/to any pointer type.

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