问题描述
我有一个模板方法，旨在使用一组特定的类。因为我没有真正需要运行时多态性，我决定不使用指针的父类，而是将编译器把一切为了我。
I have a template method that is designed to work with a specific set of classes. Since I have no real need for runtime polymorphism, I've decided to not use pointers to the parent class, but rather will have the compiler put everything together for me.
我想要限制可传递给模板的类型，或者在传递不正确的类型时使GCC问题产生明显的错误。
I want to either restrict the type that can be passed to the template, or make GCC issue sensible errors when an incorrect type is passed.
这是否可能？
推荐答案
是的。根据当天的具体需要，可以使用许多不同的技术。有boost :: enable_if。有MPL和static_assert ...（如果不使用C ++ 0x编译器，请使用BOOST_STATIC_ASSERT）。有Boost.Concepts。
Yes. It is possible using a number of different techniques depending on the specific needs of the day. There's boost::enable_if. There's MPL and static_assert...(use BOOST_STATIC_ASSERT if you're not using a C++0x compiler). There's Boost.Concepts.
是的。这是可能的。
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