本文介绍了您的SQL语法有误;检查与您的MariaDB服务器版本相对应的手册,以获取在'?'附近使用的正确语法.在第1行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用Java
和JDBC
创建清单系统.查询表时出现此错误.
I'm making an inventory system using Java
and JDBC
. I have got this error some how when querying a table.
下面是代码
public static void SearchUser() throws SQLException{
String ordersquery = "SELECT * FROM orders WHERE submittedBy = ?";
User userDetails = UserController.getUserDetails(username);//gets the details from user tables
if (userDetails != null){
System.out.println("----Menu----");
System.out.println();
System.out.println("1. View Orders Made By This User");
System.out.println("2. View Most Expensive Parts Currently Taken Out By This User");
System.out.println();
System.out.println("9. Go Back To Main Menu");
choice = input.nextLine();
if (choice.equals("1")){
try (
PreparedStatement stmt2 = conn.prepareStatement(ordersquery);
){
stmt2.setInt(1, userDetails.getUserId());
ResultSet rsOrders = stmt2.executeQuery(ordersquery);
if (rsOrders != null){
while (rsOrders.next()){
Order orderDetails = new Order(rsOrders.getInt("orderId"), userDetails.getUserId(), rsOrders.getInt("totalItems"), rsOrders.getInt("totalPrice"));
System.out.println("-------------------------------------");
Order.print(orderDetails);
}
}
}catch (SQLException e){
System.err.println(e);
}
}else if (choice.equals("2")){
}
}
}
推荐答案
ResultSet rsOrders = stmt2.executeQuery(ordersquery);
stmt2是您的SQL查询,为什么要传递ordersquery
将您的代码更改为以下代码
stmt2 is you sql query then why are you passing ordersquery
change your code to below code
ResultSet rsOrders = stmt2.executeQuery();
这篇关于您的SQL语法有误;检查与您的MariaDB服务器版本相对应的手册,以获取在'?'附近使用的正确语法.在第1行的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!