导出返回类的函数时出错:导出的变量具有或正在使用私有名称

问题描述

我遇到错误

在以下代码中:

export var UserApiClientModule = {
  fromConfiguration: (configuration: Configuration) => {
    @NgModule({
      providers: [
        {
          provide: BASE_PATH,
          useValue: basePath
        },
        {
          provide: Configuration,
          useValue: configuration
        },
        RegistrationApi,
        AuthApi,
        AccountApi,
        ContactsApi,
        ContactOrgsApi
      ],
      imports: [
        CommonModule,
        HttpModule
      ]
    })
    class UserApiClient { }

    return UserApiClient;
  }
}

我怀疑解决方案是以某种方式导出UserApiClient类型，但是由于在函数中声明了该类型，因此我不确定如何执行此操作.

I suspect the solution is to export the type UserApiClient somehow but I'm not sure how to do this since it's declared in a function.

推荐答案

此处的要点是:

并且因为我们返回的某些内容(不是导出的)是内部的，所以有问题.但是我们可以轻松返回其他内容，例如一些通用的界面...或者至少是神奇的 任何

And because we return something, which is not exported, is internal.. there is a problem. But we can easily return something else, e.g. some common interface ... or at least magical any

// change this
export var UserApiClientModule = {
  fromConfiguration: (configuration: Configuration) => {
    @NgModule({
    ...


// to that
export var UserApiClientModule = {                // below is the change
  fromConfiguration: (configuration: Configuration) : any => {
    @NgModule({
    ...

我宁愿声明一些通用接口 IHaveDynamicData ...实际上与此处所示的类似情况如何使用/创建动态模板以使用Angular 2.0编译动态组件?

I would prefer to declare some common interface IHaveDynamicData ... as in fact in similar case shown here How can I use/create dynamic template to compile dynamic Component with Angular 2.0?

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