用于搜索的正则表达式并获取图像的src

本文介绍了用于搜索的正则表达式并获取图像的src的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

假设我有一个包含以下代码段的html字符串。

  ...< img class =employee thumbsrc =http：//localhost/services/employee1.jpg /> ...

我想搜索这个标签是否可用，如果是的话，获取src url。 < img class =employee thumb可用于唯一标识标签。

如何在python中执行此操作？

解决方案

使用正则表达式：

 >>> import re 
>>> str ='< img class =employee thumbsrc =http：//localhost/services/employee1.jpg/>'
>>>如果re.search（'img class =employee thumb'，str）：
 ... print re.findall（'src =（。*？）'，s，re.DOTALL）
 ... 
 ['http：//localhost/services/employee1.jpg']

使用lxml：

 >>> from lxml import etree 
>>> root = etree.fromstring（
 ...< html> 
 ...< img class =employee thumbsrc =http：//localhost/services/employee1.jpg /> 
 ...< / html> 
 ...）
>>> print root.xpath（// img [@ class ='employee thumb'] / @ *）[1] 
 http：//localhost/services/employee1.jpg

Assume I am having a html string containing the following code snippet.

... <img class="employee thumb" src="http://localhost/services/employee1.jpg" /> ...

I want to search whether this tag is available and if so get the src url. <img class="employee thumb" can be used to uniquely identify the tag.

How to do this in python?

解决方案

Using Regular Expression :

>>> import re
>>> str =  '<img class="employee thumb" src="http://localhost/services/employee1.jpg" />'
>>> if re.search('img class="employee thumb"', str):
...     print re.findall ( 'src="(.*?)"', s, re.DOTALL)
... 
['http://localhost/services/employee1.jpg']

Using lxml :

>>> from lxml import etree
>>> root = etree.fromstring("""
... <html>
...     <img class="employee thumb" src="http://localhost/services/employee1.jpg" />
... </html>
... """)
>>> print root.xpath("//img[@class='employee thumb']/@*")[1]
http://localhost/services/employee1.jpg

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