问题描述
C#的新手,试图尽可能清楚地描述我的问题。
当项目启动时,Form1会自动显示,我在这里面有一行代码Program.cs
Application.Run(new Form1());
我有另一种形式Form2,它不在Program.cs中,据说,Program.cs没有任何与Form2相关的代码
在Form1中,有一个按钮SwitchFormButton,其代码如下:
Form2 f2 = new Form2();
f2.Show();
//this.Close();
//如果我在这里使用this.Close(),它实际上会关闭表单,结束应用程序,这不是我想要的。
//this.Visible = false;
//代码也不起作用,代码只是将Form1移到Form2后面,但两个表单仍然显示在窗口任务栏中。
这是我想要完成的事情:当我单击Form1按钮SwitchFormButton时,Form1应该关闭(也不会显示在任务栏中),Form2显示出来。
应该如何我这样做了吗?
谢谢。
New to C#, trying to describe my question as clearly as I can.
Form1 is shown automatically when the project starts, I have a line of code like this inside Program.cs
Application.Run(new Form1 ());
I have another form Form2, which is NOT inside Program.cs, that being said, Program.cs does not have any code related to Form2
Inside Form1, there is a button SwitchFormButton, which has below code:
Form2 f2 = new Form2(); f2.Show(); //this.Close(); //If I use this.Close() here, it actually closes both form, end application, which is not what I want. //this.Visible = false; //The code does not work either, the code merely moves Form1 behind Form2, but both forms still show up in window taskbar.
Here is what I want to accomplish: when I click the Form1 button SwitchFormButton, Form1 should be closed (not showing up in task bar either), Form2 shows up.
How should I do it?
Thanks.
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