如何快速绘制简单的圆角矩形（圆角）

问题描述

我设法绘制了一个矩形:-)但是我不知道如何绘制一个圆角的矩形。

I managed to draw a rect :-) But I don't know how to draw a rounded rect.

有人可以通过以下代码帮助我吗？

Can someone help me out with the following code how to round the rect?

let canvas = UIGraphicsGetCurrentContext()
rec = CGRectMake(0, 0, 40, 40);

//var maskPath = UIBezierPath(roundedRect: rec, byRoundingCorners: .BottomLeft | .BottomRight, cornerRadii: CGSize(width: 3, height: 3))

CGContextAddRect(canvas, rec);
CGContextFillPath(canvas);

推荐答案

///将此代码放入ur drawRect

//Put this code in ur drawRect

目标-C

 - (void)drawRect:(CGRect)rect
{

CGContextRef ctx = UIGraphicsGetCurrentContext();
CGContextSaveGState(ctx);


 CGPathRef clippath = [UIBezierPath bezierPathWithRoundedRect:CGRectMake(x,y, width, height) cornerRadius:6].CGPath;
CGContextAddPath(ctx, clippath);

CGContextSetFillColorWithColor(ctx, self.color.CGColor);

CGContextClosePath(ctx);
CGContextFillPath(ctx);

[self.color set];


[_path closePath]; // Implicitly does a line between p4 and p1
[_path fill]; // If you want it filled, or...
[_path stroke]; // ...if you want to draw the outline.
CGContextRestoreGState(ctx);
}

Swift 3

func drawRect(rect : CGRect)
{
// Size of rounded rectangle
let rectWidth = rect.width
let rectHeight = rect.height

// Find center of actual frame to set rectangle in middle
let xf:CGFloat = (self.frame.width  - rectWidth)  / 2
let yf:CGFloat = (self.frame.height - rectHeight) / 2

let ctx: CGContext = UIGraphicsGetCurrentContext()!
ctx.saveGState()

let rect = CGRect(x: xf, y: yf, width: rectWidth, height: rectHeight)
let clipPath: CGPath = UIBezierPath(roundedRect: rect, cornerRadius: rectCornerRadius).cgPath

ctx.addPath(clipPath)
ctx.setFillColor(rectBgColor.cgColor)




ctx.closePath()
ctx.fillPath()
ctx.restoreGState()

}

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