如何HTTP从Ruby中的内存中发布流数据?

问题描述

我想上传在运行时使用Ruby生成的数据，就像从块中上传上传的东西一样.

I would like to upload data I generated at runtime in Ruby, something like feeding the upload from a block.

我发现的所有示例仅显示了如何流式传输在请求之前必须在磁盘上的文件，但是我不想缓冲该文件.

All examples I found only show how to stream a file that must be on disk prior to the request but I do not want to buffer the file.

除了滚动我自己的套接字连接之外，什么是最佳解决方案?

What is the best solution besides rolling my own socket connection?

这是一个伪代码示例:

post_stream('127.0.0.1', '/stream/') do |body|
  generate_xml do |segment|
    body << segment
  end
end

推荐答案

有效的代码.

    require 'thread'
    require 'net/http'
    require 'base64'
    require 'openssl'

    class Producer
      def initialize
       @mutex = Mutex.new
       @body = ''
       @eof = false
      end

      def eof!()
        @eof = true
      end

      def eof?()
        @eof
      end

      def read(size)
        @mutex.synchronize {
          @body.slice!(0,size)
        }
      end

      def produce(str)
        if @body.empty? && @eof
          nil
        else
          @mutex.synchronize { @body.slice!(0,size) }
        end
      end
    end

    data = "--60079\r\nContent-Disposition: form-data; name=\"file\"; filename=\"test.file\"\r\nContent-Type: application/x-ruby\r\n\r\nthis is just a test\r\n--60079--\r\n"

    req = Net::HTTP::Post.new('/')
    producer = Producer.new
    req.body_stream = producer
    req.content_length = data.length
    req.content_type = "multipart/form-data; boundary=60079"

    t1 = Thread.new do
      producer.produce(data)
      producer.eof!
    end

    res = Net::HTTP.new('127.0.0.1', 9000).start {|http| http.request(req) }
    puts res

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