cvc-complex-type.2.4.c:匹配通配符严格，但找不到声明

问题描述

我正在尝试理解 xsd 中的 元素.我有两个 xsd.

图书目录.xsd

Reviewer.xsd

但是如果我根据上面的 xsd 验证下面的 cvc-complex-type.2.4.c:匹配的通配符是严格的，但是找不到元素p:Reviewer"的声明. 错误.两个 xsd 文件不应该在同一个命名空间中吗?

 解决方案 
两个选项...
选项一:如果您不想必须有p:Reviewer的定义，请添加processContents=宽松" 到您的 xs:any 元素:
 
根据 >
processContents 属性的松散值指示 
另请参见 
您还应该仔细调整您的 xsi:schemaLocation 值，以指向正在播放的每个命名空间的每个 XSD 的实际文件名.这是您的 
注意:确保 Review.xsd 中的 targetNamespace 与 BookCatalogue.xsi:schemaLocation 属性中为其声明的内容相匹配.
选项二:如果您确实想坚持p:Reviewer的定义存在，只需将上述更改为确保可以根据 xsi:schemaLocation 机制找到 Review.xsd.不需要 processContents 设置；它默认为 strict.
I am trying to understand <any> element in xsd. I had two xsds. 
Book Catalogue.xsd
<?
Reviewer.xsd
<?
But if i validate the below cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'p:Reviewer'. error.  Does both xsd file should not be in same namespace? 
<?
 解决方案 
Two options...
Option One: If you do not want to have to have the definition of p:Reviewer present, add processContents="lax" to your xs:any element:
      <xs:any namespace="##any" minOccurs="0"  processContents="lax"/>
Per 
See also 
You should also carefully adjust your xsi:schemaLocation values to point to the actual filename of each XSD for each namespace in play.  Here is your 
<?
Note: Make sure that the targetNamespace in Review.xsd matches what's declared for it in BookCatalogue.xsi:schemaLocation attribute.
Option Two: If you do want to insist that the definition of p:Reviewer be present, just make the above changes to be sure that Review.xsd can be found per the xsi:schemaLocation mechanism.  No processContents setting is required; it defaults to strict.
                        
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