异常从不抛出对应的try语句的正文

本文介绍了异常从不抛出对应的try语句的正文的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我在Java中遇到异常处理问题，这是我的代码。当我尝试运行这一行时，我收到编译器错误： throw new MojException（Bledne dane）; 。错误是：这是代码： public class Test { public static void （int i = 1; i< args.length; i ++）{尝试{ Integer.parseInt（args [i-1]）; } catch（MojException e）{抛出新的MojException（Bledne dane）; } try { WierszTrojkataPascala a = new WierszTrojkataPascala（Integer.parseInt（args [0]））; System.out.println（args [i] +：+ a.wspolczynnik（Integer.parseInt（args [i]）））; } catch（MojException e）{ throw new MojException（args [i] ++ e.getMessage（））; } } } } 这里是MojException的代码： public class MojException extends Exception { MojException（String s）{超级} } 任何人都可以帮助我吗？解决方案 try语句中的catch-block需要捕获正好 try {} -block 可以抛出（或超级类）。 try { // do something throws ExceptionA，eg 抛出新的ExceptionA（我是异常Alpha！）; } catch（ExceptionA e）{ //做某事来处理异常，例如 System.out.println（Message：+ e.getMessage（））; } 您要做的是这样的： try { throw new ExceptionB（I am Exception Bravo！）; } catch（ExceptionA e）{ System.out.println（Message：+ e.getMessage（））; } 这将导致编译器错误，因为您的java知道您正在尝试以捕获永远不会发生的异常。因此，您将得到：异常ExceptionA从不抛出对应的try语句。 I have a problem with exception handling in Java, here's my code. I got compiler error when I try to run this line: throw new MojException("Bledne dane");. The error is:Here is the code:public class Test { public static void main(String[] args) throws MojException { // TODO Auto-generated method stub for(int i=1;i<args.length;i++){ try{ Integer.parseInt(args[i-1]); } catch(MojException e){ throw new MojException("Bledne dane"); } try{ WierszTrojkataPascala a = new WierszTrojkataPascala(Integer.parseInt(args[0])); System.out.println(args[i]+" : "+a.wspolczynnik(Integer.parseInt(args[i]))); } catch(MojException e){ throw new MojException(args[i]+" "+e.getMessage()); } } }}And here is a code of MojException:public class MojException extends Exception{ MojException(String s){ super(s); }}Can anyone help me with this? 解决方案 A catch-block in a try statement needs to catch exactly the exception that the code inside the try {}-block can throw (or a super class of that).try { //do something that throws ExceptionA, e.g. throw new ExceptionA("I am Exception Alpha!");}catch(ExceptionA e) { //do something to handle the exception, e.g. System.out.println("Message: " + e.getMessage());}What you are trying to do is this:try { throw new ExceptionB("I am Exception Bravo!");}catch(ExceptionA e) { System.out.println("Message: " + e.getMessage());}This will lead to an compiler error, because your java knows that you are trying to catch an exception that will NEVER EVER EVER occur. Thus you would get: exception ExceptionA is never thrown in body of corresponding try statement. 这篇关于异常从不抛出对应的try语句的正文的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！