问题描述
我尝试将派生类型发送给处理器.该类型包含其他派生类型的对象.我从示例:结构派生数据类型开始了示例.我添加我的代码.该代码虽然很少,但是对于两种类型基本上相同.我有同时还有Particle
对象的Part
对象,我想发送Part
.我得到的结果是在代码之后.
I try to send a derived type to processors. The type contains object from other derived type. I started the example from Examples: Struct Derived Data Type. I add my code. The code is little long but it basically same for two types. I have Part
object that has also a Particle
object and i want to send Part
. The result that i have is after the code.
#include "mpi.h"
#include <stdio.h>
#define NELEM 25
main(int argc, char *argv[]) {
int numtasks, rank, source=0, dest, tag=1, i;
typedef struct {
float x, y, z;
float velocity;
int n, type;
} Particle;
// Another struct to send
typedef struct {
char character;
Particle part ;
} Part ;
MPI_Request send_req;
MPI_Status stat;
MPI_Init(&argc,&argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &numtasks);
// Particle type
Particle particles;
MPI_Datatype particletype, oldtypes[2];
int blockcounts[2];
MPI_Aint offsets[2], extent;
offsets[0] = 0;
oldtypes[0] = MPI_FLOAT;
blockcounts[0] = 4;
MPI_Type_extent(MPI_FLOAT, &extent);
offsets[1] = 4 * extent;
oldtypes[1] = MPI_INT;
blockcounts[1] = 2;
MPI_Type_struct(2, blockcounts, offsets, oldtypes, &particletype);
MPI_Type_commit(&particletype);
// Part type
Part party , party_received;
MPI_Datatype part_type,oldtype2[2];
int blockcount2[2];
MPI_Aint offset2[2],extent2;
offset2[0] = 0;
oldtype2[0] = MPI_CHAR ;
blockcount2[0] = 1 ;
MPI_Type_extent(particletype,&extent);
offset2[1] = extent ;
oldtype2[1] = particletype ;
blockcount2[1] = 1 ;
MPI_Type_struct(2,blockcount2,offset2,oldtype2,&part_type);
MPI_Type_commit(&part_type);
party.character= 'a';
if (rank == 0) {
particles.x = 1 * 1.0;
particles.y = 1 * -1.0;
particles.z = 1 * 1.0;
particles.velocity = 0.25;
particles.n = 1;
particles.type = 1 % 2;
party.part = particles;
printf("Derived data type sending, character: %c \n",party.character);
MPI_Isend(&party,1,part_type,1,tag,MPI_COMM_WORLD,&send_req);
printf("particles sent %f %f %f %f %d %d \n",
party.part.x,party.part.y,party.part.z,
party.part.velocity,party.part.n,party.part.type);
}
if(rank == 1) {
MPI_Recv(&party_received, 1, part_type, 0, tag, MPI_COMM_WORLD, &stat);
printf("derived part type received character %c \n",party_received.character) ;
printf("particles %f %f %f %f %d %d \n",
party_received.part.x,party_received.part.y,party_received.part.z,
party_received.part.velocity,party_received.part.n,party_received.part.type);
}
MPI_Type_free(&particletype);
MPI_Finalize();
}
结果每次都会更改.最后一个是:
The result changes every time. The last one is :
Derived data type sending, character: a
particles sent 1.000000 -1.000000 1.000000 0.250000 1 1
derived part type received character a
particles 0.000000 -2686527813451776.000000 0.000000 0.000000 1 1
虽然character
为true,但为什么Particle
对象不是?我该如何纠正?
While the character
is true, why Particle
object are not ? How can i correct it?
推荐答案
您错误地计算了偏移量.
You are computing the offsets wrongly.
offset2[0] = 0;
oldtype2[0] = MPI_CHAR ;
blockcount2[0] = 1 ;
MPI_Type_extent(particletype,&extent);
offset2[1] = extent ; <--- WRONG
oldtype2[1] = particletype ;
blockcount2[1] = 1 ;
此处的偏移量不是结构第二个成员的范围.这是前一个的范围+可能是一些填充(在您的情况下为3个字节的填充).
The offset here is not the extent of the second member of the structure. It is the extent of the first one + possibly some padding (in your case - 3 bytes of padding).
为防止将来出现类似错误,我建议您改用offsetof()
:
To prevent similar error in the future, I would advise you to use offsetof()
instead:
#include <stddef.h>
offset[0] = offsetof(Part, character);
offset[1] = offsetof(Part, part);
使用范围计算偏移量在概念上是错误的,因为不能保证在结构内部使用的填充与范围匹配.一个简单的示例:MPI_CHAR
在大多数系统上的范围为1个字节,但是如果您具有struct { char a; int b; }
之类的结构,由于对齐要求,在a
和b
之间将有3个字节的填充.这同样适用于您的Part
结构-由于Particle
的第一个成员是浮点数,因此part
成员使用填充对齐.
Computing offsets using extents is conceptually wrong since there is no guarantee that the padding used inside structures matches the extent. A simple example: MPI_CHAR
has extent of 1 byte on most systems but if you have a structure like struct { char a; int b; }
, because of alignment requirements, there will be 3 bytes of padding between a
and b
. The same applies to your Part
structure - the part
member is aligned using padding due to the first member of Particle
being a float.
如果您的系统没有offsetof
,则可以将其替换为MPI_Get_address
:
If your system doesn't have offsetof
, you can replace it with MPI_Get_address
:
Part party;
MPI_Aint base, member_offset;
MPI_Get_address(&party, &base);
MPI_Get_address(&party.character, &member_offset);
offset[0] = member_offset - base;
MPI_Get_address(&party.part, &member_offset);
offset[1] = member_offset - base;
这篇关于MPI派生类型发送的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!