根据成员的存在选择模板函数

问题描述

假设您有这两个类:

class A
{
 public:
     int a;
     int b;
}

class B
{
 public:
     int a;
     int b;
}

class C
{
 public:
     float a1;
     float b1;
}

enum class Side { A, B };

我想要一个模板函数，它接受一个 side 和一个 T，并且根据 T，返回对Ta" 或 "Tb" 如果该类具有成员 T::a，或对 "T.a1 的引用>" 或 "T.b1" 如果类有成员 T::a1.

I want a template function which takes a side and a T, and depending on the T, returns a reference to "T.a" or "T.b" if the class has a member T::a, or a reference to "T.a1" or "T.b1" if the class has a member T::a1.

我的出发点是:

template<typename T>
auto &GetBySide(const Side &side, const T &twoSided)
{
  return side == Side::A?twoSided.a:twoSided.b;
}

template<typename T>
auto &GetBySide(const Side &side, const T &twoSided)
{
  return side == Side::A?twoSided.a1:twoSided.b1;
}

问题是如果成员 a 不存在，如何让编译器跳过第一个模板.

The question is how to get the compiler to skip the first template if the member a does not exist.

所以我实现了下面@Jarod42 给出的解决方案，但它在 VS 2015 中给出了错误，因为 VS 区分模板的能力存在错误.这是一个解决方法:

So I implemented the solution given by @Jarod42 below, but it gave errors in VS 2015 because of a bug in VS ability to differentiate between templates. Here is a work around:

template<typename T>
auto GetBySide(const Side &side, const T& twoSided)
-> decltype((twoSided.a))
{
  return side == Side::A ? twoSided.a : twoSided.b;
}

// Using comma operator to trick compiler so it doesn't think that this is the same as above
template<typename T>
auto GetBySide(const Side &side, const T &twoSided)
-> decltype((0, twoSided.a1))
{
  return side == Side::A ? twoSided.a1 : twoSided.b1;
}

// See comment above
template<typename T>
auto GetBySide(const Side &side, const T &twoSided)
-> decltype((0, 0, twoSided.a2))
{
  return side == Side::A ? twoSided.a2 : twoSided.b2;
}

另一种方法是使用逗号运算符和表示每个概念"的特殊结构

Another way would be to use the comma operator and a special struct which represented each "concept"

推荐答案

使用 SFINAE.

template<typename T>
auto GetBySide(const Side &side, const T& twoSided)
-> decltype((twoSided.a))
{
  return side == Side::A ? twoSided.a : twoSided.b;
}

template<typename T>
auto GetBySide(const Side &side, const T &twoSided)
-> decltype((twoSided.a1))
{
  return side == Side::A ? twoSided.a1 : twoSided.b1;
}

演示

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