我怎样才能在同一个文件中优雅地实现多个字符串替换？

问题描述

  File.WriteAllText（filePath，Regex）
现在我有一些代码来替换看起来像这样的文件中的字符串： .Replace（File.ReadAllText（filePath），
（+ column.Key +），
+ column.Value +
））; 
 File.WriteAllText（filePath，Regex.Replace（File.ReadAllText（filePath），
（\\ [\+ column.Key +\\\] ），
[\+ column.Value +\]
））; 
  

然而，每个替换打开和关闭文件，似乎偶尔他们运行太快而且一个替换将不起作用，因为该文件在以前的字符串替换中还没有关闭。有没有我可以重复使用的代码解决这个问题，也许使用FileStream类（所以我可以打开和关闭一次）？或建议更好的方式来做到这一点？只是想知道是否有更简单的办法可以做，而不必创建字符串数组，我想要替换和写入代码读取，写入，并通过手动查找字节。谢谢。

解决方案

string contents = File.ReadAllText（filePath）;
contents = Regex.Replace（contents，
（+ column.Key +），
+ column.Value +）;
contents = Regex.Replace（contents，
（\\ [\+ column.Key +\\\）），
[ \+ column.Value +\]）;
File.WriteAllText（filePath，contents）;


Currently I have some code to replace strings in a file that looks like this:

File.WriteAllText(filePath, Regex.Replace(File.ReadAllText(filePath),
    "( " + column.Key + " )",
    " " + column.Value + " "
));
File.WriteAllText(filePath, Regex.Replace(File.ReadAllText(filePath),
    "(\\[\"" + column.Key + "\"\\])",
    "[\"" + column.Value + "\"]"
));

However, each replacement opens and closes the file, and it seems that occasionally they run "too fast" and one replacement will not work because the file did not close yet in a previous string replacement. Is there any code I can reuse that solves this issue, perhaps using the FileStream class (so I can open and close once)? Or suggestions on a better way to do this? Just wondering if there is something simpler I can do than having to create byte arrays of the strings I want to replace and writing code to read, write, and seek through bytes manually. Thanks.

解决方案

string contents = File.ReadAllText(filePath);
contents = Regex.Replace(contents,
    "( " + column.Key + " )",
    " " + column.Value + " ");
contents = Regex.Replace(contents,
    "(\\[\"" + column.Key + "\"\\])",
    "[\"" + column.Value + "\"]");
File.WriteAllText(filePath, contents);

这篇关于我怎样才能在同一个文件中优雅地实现多个字符串替换？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！