问题描述
在java中,从String中解析数字是非常简单的,即如果字符串的格式为'n'或' - n',则使用Integer.parseInt(s) ,但不幸的是,它不能以'+ n'的格式解析字符串。
那么什么是最有效/优雅的解析方式如果它包含正面或负面的前缀,那么在java中的字符串的数字:'+ n'或' - n'? Integer.parseInt(s.replace(+,));
实际上有很多使用Integer来解析数字的问题,因为Integer具有非常特定的边界的大小和格式(1,000,000.00)不解析这种方式,但我把你的问题作为Integer.parseInt满足你的需要就好了,你只需要处理您的数据+。 b $ b
It's quite straight forward in java to parse number from String, i.e. with Integer.parseInt(s) if string in the format 'n' or '-n', but unfortunately it fails to parse string in the format of '+n'.
So what is the most effective/elegant way to parse number from string in java if it contains positive or negative prefix: '+n' or '-n' ?
Integer.parseInt(s.replace("+", ""));
In truth there are many gotchas using Integer to parse numbers like that, in that Integer has very specific bounds of size and format ("1,000,000.00") isn't parsing that way, but I'm taking your question as Integer.parseInt meets your needs just fine, you just have to deal with a + in your data.
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