本文介绍了R: ggplot 在 x 轴上显示所有日期的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下数据集
structure(list(Date = structure(c(16636, 16667, 16698, 16728,
16759, 16789, 16820, 16851, 16880, 16911, 16636, 16667, 16698,
16728, 16759, 16789, 16820, 16851, 16880, 16911, 16636, 16667,
16698, 16728, 16759, 16789, 16820, 16851, 16880, 16911, 16636,
16667, 16698, 16728, 16759, 16789, 16820, 16851, 16880, 16911,
16636, 16667, 16698, 16728, 16759, 16789, 16820, 16851, 16880,
16911), class = "Date"), Wheel = structure(c(5L, 5L, 5L, 5L,
5L, 5L, 5L, 5L, 5L, 5L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L,
12L, 12L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 11L, 11L, 11L,
11L, 11L, 11L, 11L, 11L, 11L, 11L, 6L, 6L, 6L, 6L, 6L, 6L, 6L,
6L, 6L, 6L), .Label = c("L1", "L2", "L3", "L4", "L5", "L6", "R1",
"R2", "R3", "R4", "R5", "R6"), class = "factor"), WearRate = c(-0.000367,
0, 0, 0, 0.001888, 0, -0.00018, 0.000579, -0.000211, 0.000643,
0.000106, 0, 0, 0, 0.000833, 0, -0.00036, 0.000811, -0.000819,
0.002044, -0.00029, 0, 0, 0, 0.001666, 0, -0.000348, 0.000888,
-0.000679, 0.001636, 8.7e-05, 0, 0, 0, 0.000666, 0, -0.000315,
0.000618, -0.000585, 0.001636, -0.000512, 0, 0, 0, 0.002499,
0, -0.000247, 0.000734, -9.4e-05, 0.000409)), .Names = c("Date",
"Wheel", "WearRate"), row.names = 211269:211318, class = "data.frame")
我正在尝试绘制 Date vs WearRate
和 color by Wheel
的图.代码如下:
I am trying to make a plot of Date vs WearRate
and color by Wheel
. The code is as follows:
ggplot(data = df) + geom_point(mapping = aes(x = Date, y = WearRate, color = Wheel))
它有效,但我想放置实际的日期标签.我该怎么做?
It works but I want to put actual date labels. How do I do it?
编辑
该图目前看起来如此处所示.但是,我想在 X 轴上看到2015 年 8 月"、2015 年 9 月"等,并且我想显示所有刻度.
The plot currently looks as shown here. However, I want to see "Aug 2015", "Sep 2015" etc on X axis and I want to display all the ticks.
推荐答案
最简单的方法是使用 scale_x_date
ggplot(data = df) +
geom_point(mapping = aes(x = Date, y = WearRate, color = Wheel))+
scale_x_date(date_labels="%b %y",date_breaks ="1 month")
%b
:月份的缩写%y
:没有世纪的年份
有关完整可能性的描述,请参阅 ?strftime()
%b
: Abbreviated month name%y
: Year without century
For a description of the full possibilities see ?strftime()
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