问题描述
在不使用plpgsql的情况下，我试图在pgsql SELECT语句中对给定文本进行urlencode.
Without using plpgsql, I'm trying to urlencode a given text within a pgsql SELECT statement.
此方法的问题:
select regexp_replace('héllo there','([^A-Za-z0-9])','%' || encode(E'\\1','hex'),'g')
...是编码函数未传递regexp参数，除非存在另一种从替换表达式内部调用函数的方法，该方法实际上是有效的.因此，我想知道是否存在一个替换表达式，该表达式本身可以将匹配项编码为十六进制值.
...is that the encode function is not passed the regexp parameter, unless there's another way to call functions from within the replacement expression that actually works. So I'm wondering if there's a replacement expression that, by itself, can encode matches into hex values.
可能还有其他功能组合.我以为那里会有一个聪明的正则表达式(也许仍然是答案)，但是我很难找到它.
There may be other combinations of functions. I thought there would be a clever regex (and that may still be the answer) out there, but I'm having trouble finding it.
推荐答案
select regexp_replace(encode('héllo there','hex'),'(..)',E'%\\1','g');
但这不会使字母数字字符易于理解.
This doesn't leave the alphanumeric characters human-readable, though.
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