0-23小时军事时钟到标准时间（hh：mm）

问题描述

我将如何进行此过程？假设有人输入 3：5，我应该可以得到输出 3:05 AM。或者，如果有人输入 00:00，我应该得到 12:00 AM。如果将时间格式简单地输入为 hhmm，我就会意识到有很多解决方法，但是输入的范围可以是 h：m， hh：m， hh：m和 hh：毫米。

How would I go about this process? Let's say that someone types in "3:5", and I should be able to get the output "3:05 AM". Or if someone types in "00:00", I should get "12:00 AM". I realize the plethora of ways to go about this if the time format was simply input as "hhmm", but the input can range from "h:m", "hh:m", "hh:m", and "hh:mm". So it's very situational.

def timeConvert():
    miliTime = int(input("Enter a time in hh:mm (military) format: "))
    miliTime.split(":")
    if len(miliTime) == 3:
        hours = miliTime[0]
        minutes = miliTime[2]
        if hours < 0:
            print("Hours can't be less than 0.")
    elif len(miliTime) == 4:
        if miliTime[0:2] >= 10:
            hours = militime[0:2]
            minutes = militime[3]
            if minutes < 0:
                print("Minutes can't be less than 0.")
            if minutes < 10:
                minutes = 0 + minutes
        else:
            hours = miliTime[0]
            minutes = militime[2:]
            if minutes >= 60:
                print("Too big of a number for minutes.")
    else:
        hours = miliTime[0:2]
        minutes = miliTime[3:]
    setting = AM
    if hours > 12:
        setting = PM
        hours -= 12
    print(hours + ":" + minutes + setting)

timeConvert()

推荐答案

用分隔输入：，并最终使用格式化的输出：

Split the input by :, and use formatted output in the end:

def timeConvert():
    miliTime = input("Enter a time in hh:mm (military) format: ")
    hours, minutes = miliTime.split(":")
    hours, minutes = int(hours), int(minutes)
    setting = "AM"
    if hours > 12:
        setting = "PM"
        hours -= 12
    print(("%02d:%02d" + setting) % (hours, minutes))

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